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3 years ago

Closed clusters are groups of closely grouped stars that are located along the spiral disk of a galaxy.

1 answer:

5 0

False. Closed clusters are groups of closely grouped stars located in the halo of a galaxy, not along the spiral disk. Open clusters are groups of loosely associated stars located along the spiral disk of a younger galaxy with active star formation.

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Rock at the edge of a cliff has kinetic energy because of its position. True False

LenaWriter [7]

its false rock is at edge

8 0

3 years ago

A tennis racquet swung with an angular velocity of 12 rad/s strikes a motionless ball at a distance of 0.5 m from the axis of ro

Anestetic [448]

Answer:

The linear velocity of the racquet at the point of contact with the ball is 6 m/s.

Explanation:

Given;

angular velocity of the racquet, ω = 12 rad/s

distance of strike, r = 0.5 m

The linear velocity of the racquet at the point of contact is given by;

V = ωr

V = (12)(0.5)

V = 6 m/s

Therefore, linear velocity of the racquet at the point of contact with the ball is 6 m/s.

8 0

3 years ago

Both matter and energy can eneter and exit which of the following systems?

pochemuha

Both matter and energy can eneter and exit an Open System only. A.

3 0

3 years ago

g The electric field in a sinusoidal wave changes as E =125 N>C2cos 311.2 * 1011 rad>s2t +14.2 * 102 rad>m2x] (a) In wh

joja [24]

Answer:

a) the propagation direction is x, b) E₀ = 125 N / C² , c) B = 41.67 10⁻⁸ T ,

d) f = 4.95 10¹¹ Hz, e) λ = 4.42 10⁻³ m, f) the speed of light ,

Explanation:

The equation they give for the sine wave is

E = 125 cos (14.2 10² x - 311.2 10¹¹ t)

This expression must have the general shape of a traveling wave

E = Eo cos (kx - wt + Ф)

we can equal each term between the two equations

a) the propagation direction is x, since it is the term that accompanies the vector k

b) the amplitude is the coefficient before the cosine function

E₀ = 125 N / C²

c) to find the amplitude of the magnetic field we use that the two fields are in phase

C = E / B

B = E / c

B = 125/3 10⁸

B = 41.67 10⁻⁸ T

d) the angular velocity is

w = 311.2 10¹¹ rad / s

angular velocity and frequencies are related

w = 2π f

f = w / 2π

f = 311.2 10¹¹ / 2π

f = 4.95 10¹¹ Hz

e) the wavelength is obtained from the wave number

k = 2π /λ

k = 14.2 10² rad / m

λ = 2π / k

λ = 2π / 14.2 10²

λ = 4.42 10⁻³ m

f) the speed of an electromagnetic wave is the speed of light

g) what is a transverse wave

5 0

3 years ago

A small object moves along the x-axis with acceleration ax(t) = −(0.0320m/s3)(15.0s−t). At t = 0 the object is at x = -14.0 m an

Ber [7]

Complete Question

A small object moves along the x-axis with acceleration ax(t) = −(0.0320m/s3)(15.0s−t)−(0.0320m/s3)(15.0s−t). At t = 0 the object is at x = -14.0 m and has velocity v0x = 7.10 m/s. What is the x-coordinate of the object when t = 10.0 s?

Answer:

The position of the object at t = 10s is $X = 38.3 \ m$