Answer:
or 
.
Explanation:
<u>Given:</u>
- Charge on the particle at origin = Q.
- Mass of the moving charged particle,
- Charge on the moving charged particle,
- Distance of the moving charged particle from first at t = 0 time,
- Speed of the moving particle,
For the moving particle to circular motion, the electrostatic force between the two must be balanced by the centripetal force on the moving particle.
The electrostatic force on the moving particle due to the charge Q at origin is given by Coulomb's law as:
where, 
is the Coulomb's constant having value 
The centripetal force on the moving particle due to particle at origin is given as:
For the two forces to be balanced,
idksbabgdsamh vjd,hba sh,gdk,h agshcg dhbmbkdgh ,mhfcdgs m,hdfgs kjhab ckjmhasb mhfcg asd,gbcfjkde qwhsfjasdhnf bkhjsadhgc kbasdhkfkiu ae jhbdkghaw gds hgu jidksbabgdsamh vjd,hba sh,gdk,h agshcg dhbmbkdgh ,mhfcdgs m,hdfgs kjhab ckjmhasb mhfcg asd,gbcfjkde qwhsfjasdhnf bkhjsadhgc kbasdhkfkiu ae jhbdkghaw gds hgu jidksbabgdsamh vjd,hba sh,gdk,h agshcg dhbmbkdgh ,mhfcdgs m,hdfgs kjhab ckjmhasb mhfcg asd,gbcfjkde qwhsfjasdhnf bkhjsadhgc kbasdhkfkiu ae jhbdkghaw gds hgu jidksbabgdsamh vjd,hba sh,gdk,h agshcg dhbmbkdgh ,mhfcdgs m,hdfgs kjhab ckjmhasb mhfcg asd,gbcfjkde qwhsfjasdhnf bkhjsadhgc kbasdhkfkiu ae jhbdkghaw gds hgu j
Answer:
a. water
Explanation:
A buoy is a floating object that is used in the sea to locate some point or as a checkpoint. It stays at its designated position in the sea by means of an anchor chain. This chain is made short in length according to the water depth do the buoy can not deviate much from its position. The same mechanism can be applied to the metal ion. When a metal ion is formed it remains at its place, but the electrons are mobile and they travel when they get a medium. For example in circuits or from one atom to other. And for the case of buoy, the water serves as electrons as the water is moving in the medium. Hence, the second analogy will be:
electrons : water
So, the correct option is:
<u>a. water</u>
1.Light-collecting area
2.Angular resolution
Explanation:
As the given spheres are connected by a thin wire so, the potential on the spheres are the same.
......... (1)
Hence, total charge will be as follows.
= Q = -95.5 nC .......... (2)
Using the above two equations, the final equation will be as follows.
and, 
Hence, we will calculate the charge on sphere B after the equilibrium is reached as follows.
= 
= 82.714 nC
Thus, we can conclude that the charge on sphere B after equilibrium has been reached is 82.714 nC.
