1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sergeu [11.5K]
4 years ago
5

The cylinder rotates about the fixed z-axis in the direction indicated. If the speed of point A is vA = 2.7 ft/sec and the magni

tude of its acceleration is aA = 20.6 ft/sec2, determine the magnitudes of the angular velocity and angular acceleration of the cylinder. Is knowledge of the angle θ necessary?
Physics
1 answer:
ASHA 777 [7]4 years ago
8 0

Answer:

7.63 rad / s

58.2 rad/s^2

Explanation:

v = 2.7 ft/s

a = 20.6 ft/s^2

Let w be the angular velocity and r be the radius of cylinder.

As we know that

v = r w

a = r w^2

So,

2.7 = r w ..... (1)

20.6 = r w^2   ....(2)

Divide equation (2) by equation (1), we get

20.6 / 2.7 = w

w = 7.63 rad / s

Put in equation (1)

r = 2.7 / 7.63 = 0.354 ft

Angular acceleration = a / r = 20.6 / 0.354 = 58.2 rad/s^2

You might be interested in
The battery for a certain cell phone is rated at 3.70 V. According to the manufacturer it can produce math]3.15 \times 10^{4} J[
AysviL [449]

Answer:

The average current that this cell phone draws when turned on is 0.451 A.

Explanation:

Given;

voltage of the phone, V = 3.7 V

electrical energy of the phone battery, E = 3.15 x 10⁴ J

duration of battery energy, t = 5.25 h

The power the cell phone draws when turned on, is the rate of energy consumption, and this is calculated as follows;

P = \frac{E}{t}

where;

P is power in watts

E is energy in Joules

t is time in seconds

P = \frac{3.15*10^4}{5.25*3600s} = 1.667 \ W

The average current that this cell phone draws when turned on:

P = IV

I = \frac{P}{V} =\frac{1.667}{3.7} = 0.451 \ A

Therefore, the average current that this cell phone draws when turned on is 0.451 A.

5 0
4 years ago
A 1250 kg car is pulling a 325 kb trailer. The car and trailer have an acceleration of 2,15m/sec2 together. Determine the net fo
xenn [34]

To solve this problem we will apply the definition of Newton's second law, which says that force is equivalent to body mass by acceleration. In this case the mass of the trailer is 325Kg and its acceleration is 2.15m / s ^ 2, so we will proceed to replace and multiply these values to find the net force on this object.

F= ma

F= (325 kg)(2.15 m/s^2)

F= 698.75N

Under the reference system in which the direction of travel is the positive direction, the direction of the force will be positive.

7 0
3 years ago
Which of the following are basic solutions? Check all that apply. A. Laundry detergent B. Vinegar C. Drain cleaner D. Antacids
ratelena [41]
A laundry detergent
B vinegar
4 0
4 years ago
Which theory states that if you are forced to smile at an event, you will enjoy it? A. The Schachter-Singer theory B. The Lazaru
Ronch [10]

Answer:

C. The facial feedback theory

Explanation:

The facial feedback theory as postulated by William James and connects back to the famous Charles Darwin talks about how facial expressions stimulate our emotional state of being. Based on this theory, the emotional experiences we have are determined by the looks on our faces.

According to the question, smiling at an event makes you enjoy it is an example of what the The facial feedback theory is explaining. Furthermore, smiling, which is a facial expression causes or stimulates an emotional state of enjoyment in that event.

7 0
3 years ago
The wave function of a particle is exp(i(kx-omegat)), where x is distance, t is time, and k and co are positive real numbers. Th
Step2247 [10]

Answer:

Momentum, p=\hbar k

Explanation:

The wave function of a particle is given by :

y=exp[i(kx-\omega t)]...............(1)

Where

x is the distance travelled

t is the time taken

k is the propagation constant

\omega is the angular frequency

The relation between the momentum and wavelength is given by :

p=\dfrac{h}{\lambda}............(2)

From equation (1),

k=\dfrac{2\pi}{\lambda}

\lambda=\dfrac{2\pi}{k}

Use above equation in equation (2) as :

p=\dfrac{h k}{2\pi }

Since, \dfrac{h}{2\pi}=\hbar

p=\hbar k

So, the x-component of the momentum of the particle is \hbar k. Hence, this is the required solution.

8 0
4 years ago
Other questions:
  • Which one of the following accurately describes the force of gravity? A. The gravity acceleration has no effect on a body moving
    6·2 answers
  • A teacher explains that a scientist named Boyle did many experiments to determine what the relationship is between the volume an
    11·1 answer
  • An electron enters a region of space containing a uniform 0.0000193-T magnetic field. Its speed is 121 m/s and it enters perpend
    12·1 answer
  • A plane flying horizontally above earth’s surface at 100. meters per second drops a crate. the crate strikes the ground 30.0 sec
    9·1 answer
  • A battery has a terminal voltage of 12.0 V when no current flows. Its internal resistance is 2.0 Ω. If a 7.2 Ω resistor is conne
    9·1 answer
  • What does it mean if one person has a higher value for power?
    14·2 answers
  • A 500-kg, light-weight helicopter ascends from the ground with an acceleration of 2.00 m/s2. over a 5.00-s interval, what is (a)
    15·1 answer
  • An electric field of intensity 3.25 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.
    9·1 answer
  • List each of the parts of the electromagnetic spectrum in order of lowest to highest frequency. Write down one use for each one,
    12·1 answer
  • A merry-go-round rotates at the rate of 0.17 rev/s with an 79 kg man standing at a point 1.6 m from the axis of rotation.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!