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jolli1 [7]
3 years ago
14

A gas has an initial volume of 212 cm3 at a temperature of 293 K and a pressure of 0.98 atm. What is the final pressure of the g

as if the volume decreases to 196 cm3 and the temperature of the gas increases to 308 K? 0.86 atm 0.95 atm 1.0 atm 1.1 atm
Physics
2 answers:
PIT_PIT [208]3 years ago
8 0

Answer: 1.1 atm

Explanation:

Using ideal gas equation:

\frac{P_1V_1}{T_1}={P_2V_2}{T_2}

P_1 = initial pressure = 0.98 atm

V_1 = initial volume = 212cm^3

T_1 = initial temperature= 293 K

P_2 = final pressure = ?

V_2 = final volume= 196cm^3

T_2 = final temperature=308 K

\frac{0.98\times 212}{293}={P_2\times 196}{308}

P_2= 1.1atm

Thus final pressure of the gas is 1.1 atm.

Serggg [28]3 years ago
7 0
If the ga has 212 cm3 the. Temperature was at a 2
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The dentisty of an object relies on both the _________ of the object.
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2 years ago
The sun is 60° above the horizon. Rays from the sun strike the still surface of a pond and cast a shadow of a stick that is stuc
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5 0
3 years ago
What is the acceleration of an object with a mass of
aev [14]

Heya!!

For calculate aceleration, lets applicate second law of Newton:

                                                    \boxed{F=ma}

                                                 <u>Δ   Being   Δ</u>

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⇒ Let's replace according the formula and clear "a":

\boxed{a=183 \ N / 367\ kg}

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Result:

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Good Luck!!

3 0
3 years ago
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