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GrogVix [38]
4 years ago
11

An example of a single displacement reaction is

Physics
2 answers:
g100num [7]4 years ago
6 0
Single Displacement Reaction Definition. A single displacement reaction is a chemical reaction where one reactant is exchanged for one ion of a second reactant. It is also known as a single replacement reaction.

Eduardwww [97]4 years ago
6 0

Answer:

Answered

Explanation:

A single replacement reaction one element replaces another in a single compound. This type reaction has the general reaction:

A+BC→AC + B

in this reaction B is replaced by A in the compound BC.

An example of such type of reaction is when potassium reacts with water.

2K + H20→ 2KOH + H2

In this reaction one atom of hydrogen of water is replaced by potassium.

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2. A car accelerates uniformly from +10.0 m/s to +50.0 m/s over a distance of 225 m. How long did it take to go that distance? S
artcher [175]
Let's call the constant acceleration a.
At a time t, its speed will thus be v(t)=a*t+v0 where v0 is its initial speed, here 10 m/s. Hence v(t)=a*t+10.

From there we can deduce the position P(t)=a*t^2/2+10t+p0 where p0 is the initial position, here 0.

Hence P(t)=a*t^2/2+10t

Let's call T the time at which it's at 50 m/s, we know that P(T)=225m and that v(T)=50 m/s hence a*T+10=50 thus a=40/T and P(T)=(40/2+10)T=30T

Hence T=225/30=7.5

It took 7.5 seconds


7 0
3 years ago
Why are potassium molecules likely to enter a red blood cell?
noname [10]
<span>they have to be selective permeable to filter out the waste products but allow the nutrients and blood cells to pass through. </span>
5 0
3 years ago
Describe an example of newton’s 3rd law of motion
professor190 [17]

Answer:

For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.

Explanation:

8 0
3 years ago
In __________ waves, the motion of the particles in a medium is along the direction of the wave (parallel). *
True [87]
Longitude is the answer

7 0
3 years ago
Particle A and particle B are held together with a compressed spring between them. When they are released, the spring pushes the
leonid [27]

Answer:

KE_A=33\ J

KE_B=99\ J

Explanation:

Given:

Let mass of the particle B be, m_B=m

then the mass of particle A, m_A=3m

Energy stored in the compressed spring, E=132\ J

Now when the compression of the particles with the spring is released, the spring potential energy must get converted into the kinetic energy of the particles and their momentum must be conserved.

Kinetic energy:

\frac{1}{2}m_A.v_A^2+\frac{1}{2}m_B.v_B^2=132

3m.v_A^2+m.v_B^2=264 .............................(1)

<u>Using the conservation of linear momentum:</u>

m_A.v_A+m_B.v_B=0

3m.v_A+m.v_B=0 .............................(2)

Put the value of v_A from eq. (2) into eq. (1)

3m\times (\frac{-v_B}{3})^2+m.v_B^2=264

v_B^2=\frac{198}{m}  ...........................(3)

<u>Now the kinetic energy of particle B:</u>

KE_B=\frac{1}{2}\times m_B\times v_B^2

KE_B=\frac{1}{2}\times m\times \frac{198}{m}

KE_B=99\ J

Put the value of v_B^2 form eq. (3) into eq. (1):

v_A^2=\frac{22}{m}

<u>Now the kinetic energy of particle A:</u>

<u />KE_A=\frac{1}{2}m_A.v_A^2<u />

<u />KE_B=\frac{1}{2}\times 3m\times \frac{22}{m}<u />

KE_A=33\ J

6 0
3 years ago
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