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3 years ago

An example of a single displacement reaction is

Physics

2 answers:

g100num [7]3 years ago

6 0

Single Displacement Reaction Definition. A single displacement reaction is a chemical reaction where one reactant is exchanged for one ion of a second reactant. It is also known as a single replacement reaction.

Eduardwww [97]3 years ago

6 0

Answer:

Answered

Explanation:

A single replacement reaction one element replaces another in a single compound. This type reaction has the general reaction:

A+BC→AC + B

in this reaction B is replaced by A in the compound BC.

An example of such type of reaction is when potassium reacts with water.

2K + H20→ 2KOH + H2

In this reaction one atom of hydrogen of water is replaced by potassium.

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If you exert 250J of work onto a lever that is 5m long, what amount of force are you applying?

maks197457 [2]

From the formula of W = F·d , becuase we have the values for W and d we can find F

W = F·d
F= W/d
= 250/5
= 50 N

40 N of force was applied

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2 years ago

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Which of the following graphs represents constant positive acceleration

nika2105 [10]

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3 years ago

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2 years ago

The flywheel of an engine has moment of inertia 2.50 kg m2 about its rotation axis. What constant torque is required to bring it

MrRissso [65]

Answer:

Explanation:

From the question we are told that

The moment of inertia is $I = 2.50 \ kg \cdot m^2$

The final angular speed is $w_f = 400 rev/min = \frac{400 * 2\pi}{60} = 41.89 \ rad/s$

The time taken is $t = 8.0 s$

The initial angular speed is $w_i = 0\ rad/s$

Generally the average angular acceleration is mathematically represented as

$\alpha = \frac{w_f - w_i }{t}$

=> $\alpha = \frac{41.89}{8}$

=> $\alpha = 5.24 \ rad/s^2$

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$\tau = I * \alpha$

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2 years ago

The gap between electrodes in a spark plug is 0.060 cm. Producing an electric spark in a gasoline-air mixture requires an electr

VladimirAG [237]

The minimum potential difference must be supplied by the ignition circuit to start a car is -1800 V

<u>Explanation:</u>

Given data,

E= 3 ×10 ⁶ Δx=0.06/100

We have to find the minimum potential difference

E= -ΔV/Δx

ΔV=- E × Δx

ΔV =-3 ×10 ⁶ . 0.06/100

ΔV=-1800 V

The minimum potential difference must be supplied by the ignition circuit to start a car is -1800 V

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2 years ago