All categories

3 years ago

Can you pleaseeeee solve (x-5)^2=3

Mathematics

2 answers:

lisabon 2012 [21]3 years ago

7 0

Answer:

x = 5±sqrt(3)

Step-by-step explanation:

(x-5)^2=3

Take the square root of each side

sqrt((x-5)^2)=±sqrt(3)

x-5 = ±sqrt(3)

Add 5 to each side

x-5 +5= 5±sqrt(3)

x = 5±sqrt(3)

son4ous [18]3 years ago

5 0

Answer:

$\huge\boxed{x=5-\sqrt3\ \vee\ x=5+\sqrt3}$

Step-by-step explanation:

$(x-5)^2=3\iff x-5=\pm\sqrt3\qquad\text{add 5 to both sides}\\\\x-5+5=-\sqrt3+5\ \vee\ x-5+5=\sqrt3+5\\\\x=5-\sqrt3\ \vee\ x=5+\sqrt3$

You might be interested in

What other information do you need in order to prove the triangles congruent using the SAS congruence postulate?

ziro4ka [17]

Answer:

I think D

Step-by-step explanation:

I think that the answer is D, since the angles are not visibly shown to be equal. If you knew answer D, you would then be able to see that segments BC and CD are congruent. I am not 100% sure, however.

4 0

3 years ago

9. Simplify (x2 + 16)(x2 – 16) = ?

OleMash [197]

4x to the second power minus 256

5 0

3 years ago

The discount on a new computer was $150. This was a discount of 23 %. Step 1 of 3: What was the original selling price of the co

disa [49]

So, it is asking for 150 is 23% of what
So, the answer is 652.17
I think
Hope this helps :D

3 0

3 years ago

Read 2 more answers

This is Matrix for pre calc

gavmur [86]

The given system of equations in augmented matrix form is

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\-6&1&2&4&-12\\1&-3&-3&5&-20\\-2&5&6&0&12\end{array}\right]$

If you need to solve this, first get the matrix in RREF:

Add 2(row 1) to row 2, row 1 to -3(row 3), and 2(row 1) to 3(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&11&5&-13&37\\0&19&10&4&-10\end{array}\right]$

Add 11(row 2) to -5(row 3), and 19(row 1) to -5(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&-164&132&-1052\end{array}\right]$

Add 164(row 3) to -91(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&13080&-39240\end{array}\right]$

Multiply row 4 by 1/13080:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&1&-3\end{array}\right]$

Add -153(row 4) to row 3:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&0&-364\\0&0&0&1&-3\end{array}\right]$

Multiply row 3 by -1/91:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Add 6(row 3) and -8(row 4) to row 2:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&0&0&-10\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Multiply row 2 by 1/5:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Add -2(row 2), 4(row 3), and -2(row 4) to row 1:

$\left[\begin{array}{cccc|c}3&0&0&0&3\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Multiply row 1 by 1/3:

$\left[\begin{array}{cccc|c}1&0&0&0&1\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

So the solution to this system is $(w,x,y,z)=(1,-2,4,-3)$ .

6 0

4 years ago

In the equation, 6(3x+5) -4x =35 , what are some of the steps that should be taken to solve for x? Select all that apply.

Natalija [7]

You need to combine like terms and subtract 30. How you find the answer is you work the problem first 1. Distribute the 6 (18x+30)-4x=35 then 2. combine like terms 18x and -4x. (14x+30)=35 then 3. Subtract 30 from both sides (14x)=5

6 0

3 years ago