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4 years ago

A/an _______ bond allows metals to conduct electricity

1 answer:

7 0

n a metallic bond, atoms of the metal are surrounded by a constantly moving "sea of electrons." This moving sea of electrons enables the metal to conduct electricity.
Answer: Metallic

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Convert to moles: 100.0g Ca3(PO4)2

salantis [7]

Answer:

0.322 moles

Explanation:

Given Mass, m = 100 g

The molar mass of Ca₃(PO₄)₂

Ca₃(PO₄)₂ = (3 x 40.08) + (2 x 30.97) + (8 x 16.00)

M = 310.18 g/mol

Let there are n number of moles,

n = given mass/ molar mass

$n=\dfrac{100 }{310.18 }\\\\n=0.322\ mol$

So, there are 0.322 moles.

6 0

3 years ago

Pls help I will give brainlist

frez [133]

Answer:

I would say B but i am not sure hope it helps

Explanation:

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3 years ago

Tell me If you get this Joke. Road Work Ahead. I SURE HOPE IT DOES! LOL LOL!:)))):)))

coldgirl [10]

Yessss vibe the goood old days

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3 years ago

Read 2 more answers

An oxygen molecule consists of two oxygen atoms, (O2), whose total mass is 5.3 × 10–26 kg and whose moment of inertia about an a

Katena32 [7]

Answer : The distance between the two atoms is $1.2\times 10^{-10}m$

Explanation :

The The formula used for moment of inertia for one atom is:

$I=(\frac{m}{2})r^2$

The formula used for moment of inertia for two atom is:

$I=2(\frac{m}{2})r^2$

where,

I = moment inertia = $1.9\times 10^{-46}kg.m^2$

r = distance of atom from axis of rotation

m = mass of atom = $5.3\times 10^{-26}kg$

Now put all the given values in the above formula, we get:

$I=2(\frac{m}{2})r^2$

$1.9\times 10^{-46}kg.m^2=2(\frac{5.3\times 10^{-26}kg}{2})r^2$

$r=6.0\times 10^{-11}m$

Now we have to calculate the distance between the two atoms.

Formula used :

$d=2r$

where,

d = distance between the two atoms

$d=2\times 6.0\times 10^{-11}m=1.2\times 10^{-10}m$

Therefore, the distance between the two atoms is $1.2\times 10^{-10}m$

3 0

4 years ago

You are given a solution of HCOOH (formic acid) with an approximate concentration of 0.20 M and you will titrate this with a 0.1

jeka57 [31]

Answer:

$\boxed{\text{36 mL}}$

Explanation:

1. Write the balanced chemical equation.

$\rm HCOOH + NaOH $ \longrightarrow$ HCOONa + H$_{2}$O$

2. Calculate the moles of HCOOH

$\text{Moles of HCOOH} =\text{20.00 mL HCOOH } \times \dfrac{\text{0.20 mmol HCOOHl}}{\text{1 mL HCOOH}} = \text{4.00 mmol HCOOH}$

3. Calculate the moles of NaOH.

$\text{Moles of NaOH = 4.00 mmol HCOOH } \times \dfrac{\text{1 mmol NaOH} }{\text{1 mmol HCOOH}} = \text{4.00 mmol NaOH}$

4. Calculate the volume of NaOH

$c = \text{4.00 mmol NaOH } \times \dfrac{\text{1 mL NaOH }}{\text{0.1105 mmol NaOH }} = \textbf{36 mL NaOH }\\\\\text{The titration will require }\boxed{\textbf{36 mL of NaOH}}$

3 0

3 years ago