How many moles are in 9.8 L of xenon gas?

Chemistry

1 answer:

mel-nik [20]2 years ago

4 0

Answer:

0.4375 moles

Explanation:

At standard temperature and pressure one mole of ideal gas occupies 22.4 L of volume.

Hence we can write following relation,

22.4 L volume is occupied by = 1 mole of Gas

So,

9.8 L of Volume will be occupied by = X mole of Gas

Solving for X,

X = 1 mole × 9.8 L / 22.4 L

X = 0.4375 moles

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Explanation:

The question is incomplete, cause you are not providing the structure. However, I found the question and it's attached in picture 1.

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For question 6a, as it was stated before, the mechanism in that reaction is a Sn2, however, we can have conditions for an E2 reaction and form an alkene. This can be done, cause the extoxide can substract the atoms of hydrogens from either the carbon of the cycle or the terminal methyl of the molecule and will form two different products of elimination. The product formed in greater quantities will be the one where the negative charge is more stable, in this case, in the primary carbon of the methyl it's more stable there, so product 1 will be formed more (See picture 2)

For question 6b, same principle of 6a, when the hydrogen migrates to the 2nd carbocation to form a tertiary carbocation the methanol will promove an E1 reaction with the vecinal carbons and form two eliminations products. See picture 2 for mechanism of reaction.