3 years ago

How many atoms are present in 179.0 g of irdium

1 answer:

4 0

1. 1.074 atoms is present in 179.0g of irdium(179.0)

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Karolina [17]

Answer:

I believe that the answer is c

Explanation:

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WINSTONCH [101]

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0.198 g CO2 plz mark me brainliest

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Misha Larkins [42]

Avogadro's law states that in a mole of any substance, there are $6.022 \times 10^{23}$ atoms. This means that in the given sample, there are

$\frac{6.075 \times 10^{26}}{6.022 \times 10^{23}}=1008.8010627 \text{ mol}$

So, the atomic mass of sulfur dioxide is

$32.06+2(15.9994=64.0588 \text{ g/mol}$

Therefore, the mass is:

$(64.0588)(1008.8010627)=\boxed{64620 \text{ g (to 4 sf)}}$

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2 years ago

ki77a [65]

The answer is B, Let me know if you get it right!

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3 years ago

My name is Ann [436]

Answer:

Explanation:

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3 years ago