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Nataly [62]
3 years ago
8

Which gas sample STP has the same total number of molecules at 2.0 L of CO2(g) at STP

Chemistry
1 answer:
zloy xaker [14]3 years ago
8 0
<span>Answer 2 (2.0L of Cl2 (g)) is correct. Avogadro's hypothesis states that 2.0 L of Cl2 (g) occupies the same volume as 2.0 L of CO2</span>
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The density of a material is a/an ___________.
Nitella [24]

The density of a material is an intensive property.

<h3>What is intensive property?</h3>

An intensive property of matter is one that does not change with the amount of matter. It is a bulk property, which means that it is a physical property that is independent of sample size or mass. An extensive property, on the other hand, is one that is affected by sample size.

<h3>What factors influence an intensive property?</h3>

Intensive properties are those that are determined solely by the characteristics of the material and not by its quantity - for example, density, temperature, refractive index, color, and pressure. Intensive properties are not additive, which means their value does not change when the amount of material is changed.

Learn more about the intensive property here:-

brainly.com/question/24909279

#SPJ4

5 0
1 year ago
Researchers used a combustion method to analyze a compound used as an antiknock additive in gasoline. A 9.394 mg sample of the c
LuckyWell [14K]

Answer:

The percent composition of the compound is 90.5 % C and 9.5 % H

Explanation:

Step 1: Data given

Mass of compound = 9.394 mg

Mass  of CO2 yielded = 31.154 mg

Mass of H2O yielded = 7.977 mg

Molar mass of CO2 = 44.01 g/mol

Molar mass of H2O = 18.02 g/mol

Step 2: Calculate moles CO2

moles of CO2 = (0.031154 g / 44.01 g/mol) = 7.08 * 10^-4 mol CO2

Step 3: Calculate moles C

moles of C = moles of CO2 * (1 mol C / 1 mol CO2)

moles of C = 7.08 * 10^-4 mol

Step 4: Calculate moles H2O

moles of H2O = (0.007977 g / 18.02 g/mol) = 4.43 * 10^-4 mol H2O

Step 5: Calculate moles of H

moles of H = moles of H2O * (2 mol H / 1 mol H2O)

moles of H =  4.43* 10^-4 *2 = 8.86 * 10^-4 mol H

Step 6: Calculate mass of C

mass C = moles C * molar mass C

mass C = 7.08 * 10^-4 mol*12.01 g/mol

mass C = 0.0085 grams

Step 7: Calculate mass of H

mass H = moles H * molar mass H

mass H = 8.86 * 10^-4 mol*1.01 g/mol

mass H = 0.000894 grams

Step 8: Calculate total mass of compound =

0.0085 grams + 0.000894 grams = 0.009394 grams = 9.394 mg

Step 9: Calculate the percent composition:  

% C = (8.50 mg / 9.394 mg) x 100 = 90.5%  

% H = (0.894 mg / 9.394 mg) x 100 = 9.5%

The percent composition of the compound is 90.5 % C and 9.5 % H

6 0
3 years ago
What volume in L of a 0.724 M Nal solution contains 0.405 mol of Nal?
Setler [38]

Answer:

0.559 L

Explanation:

Step 1: Given data

  • Moles of sodium iodide (n): 0.405 mol
  • Molar concentration of sodium iodide (M): 0.724 M (0.724 mol/L)

Step 2: Calculate the volume of solution (V)

The molarity is equal to the moles of solute divided by the liters of solution.

M = n/V

V = n/M

V = 0.405 mol/(0.724 mol/L) = 0.559 L

4 0
2 years ago
Read 2 more answers
Q3. A bridge is built without expansion gaps.
marshall27 [118]

Answer:

Q3. A bridge is built without expansion gaps.

Explain what could happen to the bridge if the temperature became:

a) much hotter than the day it was built.

b) much colder than the day it was built.

P.s. (this is not a select option question, explain each according to the question)

5 0
3 years ago
Read 2 more answers
The valence electrons of a krypton (Kr) atom in the ground state are located in the
Korvikt [17]

I dont know the answer but i have some explanation for that question.

Since krypton is in the far right row of the periodic table, its outermost shell is full with eight electrons. This is one of the happy elements and has an electron configuration of 2-8-18-8.

8 0
2 years ago
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