What descriptive term is applied to the type of diene represented by 1,5-octadiene?
1 answer:
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The complete question is as follows: 171 g of sucrose ( MW of 342, melting point 186 oC, boiling point very high, and vapor pressure is negligible) is dissolved in one liter of water at 25 oC. At 25 oC the vapor pressure of water is 24 mmHg. Which value is closest to the vapor pressure (VP) of this solution at 25 oC?
a. 16mm Hg
b. 24mm Hg
c. 20mm Hg
d. 12mm Hg
Answer: The vapor pressure (VP) of this solution at is closest to the value 24 mm Hg.
Explanation:
Given: Mass of sucrose = 171 g
Mass of water = 1 L = 1000 g
Vapor pressure of water = 24 mm Hg
As moles is the mass of substance divided by its molar mass. Hence, moles of water (molar mass = 18.02 g) is calculated as follows.
Similarly, moles of sucrose (molar mass = 342 g/mol) is as follows.
Total moles = 55.49 + 0.5 mol = 55.99 mol
Mole fraction of water is as follows.
Formula used to calculate vapor pressure of the solution is as follows.
where,
= vapor pressure of component i over the solution
= vapor pressure of pure component i
= mole fraction of i
Substitute the values into above formula to calculate vapor pressure of water as follows.
Thus, we can conclude that the vapor pressure (VP) of this solution at is closest to the value 24 mm Hg.
Answer:
The answer to your question is 33.4 ml
Explanation:
Data
volume 1 = V1 = 42 ml
temperature 1 = T1 = 20°C
temperature 2 = T2 = -60°C
Volume 2 = V2 = x
Process
1.- Convert celsius to kelvin
T1 = 20 + 273 = 293°K
T2 = -60 + 273 = 233°K
2.- Use the Charles' law to solve this problem
Solve for V2
V2 =
3.- Substitution
V2 =
4.- Simplification
V2 =
5.- Result
V2 = 33.4ml