Question

If the y component of a vector is 36, and the angle between the vector and the x-axis is 27, what is the magnitude of the vector?

Answer 1

Answer:

79.29

Explanation:

Given that,

The y component of a vector, y = 36

The angle between the vector and the x-axis is 27.

We need to find the magnitude of a vector.

Let a and b are x and y component of a vector m. There resultant is R. So,

$R=\sqrt{a^2+b^2}$

Where

$a=c\cos\theta\ \text{and}\ b=c\sin\theta$

We have, b = 36 and θ = 27°

So,

$36=R\sin\theta\\\\R=\dfrac{36}{\sin\theta}\\\\R=\dfrac{36}{\sin(27)}\\R=79.29$

So, the magnitude of the vector is 79.29