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Volgvan
3 years ago
10

Read this because I need help pleaseeeeee !!!

Physics
1 answer:
larisa86 [58]3 years ago
4 0
There are several formulas that describe the distance, speed, and time for
a falling body.  The one I use the most happens to be the one that'll be the
most useful to solve this problem:

                                Distance = 1/2 g t²

We know the distance and we know ' g ', so we can use
this formula to find ' t '.

                                 Distance = (1/2) (gravity) (time)²

                                   (239 m) = (1/2) (3.7 m/s²) (time)²

Divide each side
by  1.85 m/s² :            (129 m) / (1.85 m/s²)  =  (time)²

                                   (129/1.85)  sec²  =  (time)²  

Take the square root
of each side:                    8.35 sec  =  time
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mafiozo [28]
The answer is “Impulse acting on it” according to the impulse-momentum theorem.
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2 years ago
What is the name of Newton's first law of motion?
Ne4ueva [31]
A) law of inertia. an object in motion stays in motion
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2 years ago
When you lift a bowling ball with a force of 61.1 N, the ball accelerates upward with an acceleration a. If you lift with a forc
gtnhenbr [62]

Answer:

the weight of the ball is w = 51.94 N ( mass = 5.3 kg)

Explanation:

Following Newton's second law:

net force = mass * acceleration = weight/gravity * acceleration

then denoting 1 and 2 as the first and second lift

F₁ - w= w/g *a₁

F₂ -w = w/g *a₂ = w/g * 2.07a

dividing both equations

(F₂- w)/(F₁ -w)= 2.07

(F₂- w) = 2.07 * (F₁ -w)

1.07*w = 2.07*F₁ - F₂

w = (2.07*F₁ - F₂ )/ 1.07

replacing values

w = (2.07*61.1 N - 70.9 N )/ 1.07  = 51.94 N

then the weight of the ball is w = 51.94 N ( mass = 5.3 kg)

7 0
2 years ago
A mercury thermometer has a glass bulb of interior volume 0.100 cm3 at 10°c. the glass capillary 10) tube above the bulb has an
Nadya [2.5K]
Initial volume of mercury is
V = 0.1 cm³

The temperature rise is 35 - 5 = 30 ⁰C = 30 ⁰K.

Because the coefficient of volume expansion is 1.8x10⁻⁴ 1/K, the change in volume of the mercury is 
ΔV = (1.8x10⁻⁴ 1/K)*(30 ⁰K)(0.1 cm³) = 5.4x10⁻⁴ cm³

The cross sectional area of the tube is
A = 0.012 mm² = (0.012x10⁻² cm²).
Therefore the rise of mercury in the tube is
h = ΔV/A
   = (5.4x10⁻⁴ cm³)/(0.012x10⁻² cm²)
   = 4.5 cm

Answer: 4.5 cm
7 0
3 years ago
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andrezito [222]

A: Human Body

C is wrong because they don’t have the tools to test it on another planet

6 0
3 years ago
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