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Volgvan
3 years ago
10

Read this because I need help pleaseeeeee !!!

Physics
1 answer:
larisa86 [58]3 years ago
4 0
There are several formulas that describe the distance, speed, and time for
a falling body.  The one I use the most happens to be the one that'll be the
most useful to solve this problem:

                                Distance = 1/2 g t²

We know the distance and we know ' g ', so we can use
this formula to find ' t '.

                                 Distance = (1/2) (gravity) (time)²

                                   (239 m) = (1/2) (3.7 m/s²) (time)²

Divide each side
by  1.85 m/s² :            (129 m) / (1.85 m/s²)  =  (time)²

                                   (129/1.85)  sec²  =  (time)²  

Take the square root
of each side:                    8.35 sec  =  time
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Answer:

An acute injury is sudden and severe such as a broken bone. A chronic injury develops and worsens over an extended period of time like shin splints

Explanation:

3 0
3 years ago
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Four forces act on a hot-air balloon, as shown
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The magnitude of the resultant force on the balloon is 374.13 N.

The given forces from the image;

  • <em>Upward force = 514 N</em>
  • <em>Downward force = 267 N</em>
  • <em>Eastward force = 678 N</em>
  • <em>Westward force = 397 N</em>

The net vertical force on the balloon is calculated as follows;

F_y = 514 \ N \ \ - \ \ 267 \ N\\\\F_y = 247 \ N

The net horizontal force on the balloon is calculated as follows;

F_x = 678 \ N \ - \ 397 \ N\\\\F_x = 281 \ N

The magnitude of the resultant force on the balloon is calculated as follows;

F = \sqrt{F_y^2 + F_x^2} \\\\F = \sqrt{(247)^2 + (281)^2} \\\\F= 374.13 \ N

Thus, the magnitude of the resultant force on the balloon is 374.13 N.

Learn more here:brainly.com/question/4404327

5 0
2 years ago
Find the net charge of a system consisting of 6.25×10^6 electrons and 7.75×10^6 protons. Express your answer using three signifi
jok3333 [9.3K]

Answer:

2.40 x 10⁻¹³ C

Explanation:

n_{e} = number of electrons = 6.25 x 10⁶

q_{e} = charge on electron = - 1.6 x 10⁻¹⁹ C

n_{p} = number of protons = 7.75 x 10⁶

q_{p} = charge on proton =  1.6 x 10⁻¹⁹ C

Net charge is given as

Q = n_{e} q_{e} + n_{p} q_{p}

Q = (- 1.6 x 10⁻¹⁹) (6.25 x 10⁶) + (1.6 x 10⁻¹⁹) (7.75 x 10⁶)

Q = 2.40 x 10⁻¹³ C

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Good morning friends​
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Good morning. Whats about you

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p=mv

?=15kg * 3m/s

          45p

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