Answer:
Explanation:
Given that,
Current measure is
i=10±0.6 Amps
And also,
R=45.0±2.0 Ω
Power dissipated by
P=i²R
Then
P=(10±0.6)²(45.0±2.0)
P=10²×45
P=450Watts
Now, calculating the uncertainty
∆P=|P| • √(2(∆i/i)²+(∆R/R)²)
∆P=450√ (2×(0.6/10)²+(2/45)²)
∆P=450√(0.0072+0.001975)
∆P=450√0.009175
∆P=43.1
The uncertainty in power is 43.1
Then,
P=450 ± 43.1 Watts
Answer:
A. Attractive
B. ( μ₀I² ) / ( 2πd )
Explanation:
A. We know that currents in the same direction attract, and currents in the opposite direction repel, according to ampere's law. In this case the current in the two wires are flowing in the same direction, and hence the force between the two wires are attractive.
B. Suppose that two wires of length and both carry the current in the same direction ( given ). In the presence of a magnetic field produced by wire 1, a force of magnitude m say, is experienced by wire 2. The magnitude of the magnetic field produced by wire 1 at distance say d, from it's axis, should thus be the following -
= μ₀I / 2πd
The force experienced by wire 2 should thus be -
= I( )
= I Sin( 90 )
= I ( μ₀I / 2πd )
Therefore the force per unit length experienced by wire 2 toward wire 1 should be ...
( / ) = ( μ₀I² ) / ( 2πd ) ... which is our solution
It traveled 200 m in 50 seconds. 200/50 can be simplified to 4 m/s!
The velocity is -4 m/s (negative because it travelled from 100 to -100 or backwards)
You have a few choices:
-- Take it out of Earth's atmosphere.
-- Put it in a tank where you pumped all the air out of it.
You can put whatever you want back in the tank, just
as long as there's no oxygen in there.
-- Besides oxygen, rusting also needs water. The humidity
(water vapor) in the air is enough to do it. So if you can
keep the air totally, totally dry around the iron, then the
oxygen alone won't make it rust.
-- All these choices do the same thing: Make sure that
oxygen and water vapor can't reach the iron. The easy
way to do that is to paint or spray something onto the
surface of the iron that keeps the air away from it.