Question

A 600kg lifts starts from rest. It moves upward for 3.00 s with a constant acceleration until it reaches its final speed of 1.55 ms^-1 . calculate the force exerted by lift motor

Answer 1

We know that,

• Force = mass× acceleration

We already have mass so let us calculate accleration experienced by it, using first equation of motion;

• v = u + at
• 1.55 = 0 + a(3)
• 1.55 = 3a
• 1.55/3 = a
• 0.51 m/s² = a

Put this in force's formula;

• f = ma
• f = 600 × 0.51
• f = 306.00
• f = 306 N

Therefore, the force exerted by the lift is 306 N.