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Contact [7]
3 years ago
6

Jasmine is the director of marketing for a chain of clothing stores. She has been given a set budget and needs to drive as many

potential customers to her website as possible. Which automated bidding strategy should she use in her campaign?
Business
1 answer:
MArishka [77]3 years ago
7 0

Answer: maximize click bidding strategy

Explanation:

Being the director of marketing, Jasmine should use “Maximize Click” bidding strategy if She has been given a set budget to drive as many potential customers as possible to her clothing stores chain website.

Maximize clicks bidding strategy is set bids to try to get you as many clicks as possible within a target spend amount that you choose.

You might be interested in
Why is vocabulary important?<br> What is Promotion?<br> Why is Promotion important in marketing?
Alenkinab [10]

Vocabulary is important because ( my opinion) using betters words instead of saying something in a more simplistic way, shows you have more knowledge on what your talking about and just makes you seem smarter in general.

Promotion is a activity that supports or provides active encouragement for the furtherance of a cause, venture, or aim

Promoting is very important in marketing because it allows whatever product or information you are trying to get out expands across to different platforms and audiences.

6 0
3 years ago
The upward-sloping portion of the long-run average cost curve is a result of:.
iogann1982 [59]

Answer:

average cost is increasing

Explanation:

7 0
2 years ago
How much must you deposit each year into your retirement account starting now and continuing through year 12 if you want to be a
Vesnalui [34]

Answer:

$2,583

Explanation:

The required value of your account at year 35 is:

$70,000 / 0.1 = $700,000

FV = $700,000. This is the required amount you need to have in your account 35 years from now

i/r = 10%. The interest that the account pays

n = 35 years

PV = 0

PMT (The amount of annual deposit required to achieve the target above. This is the missing value we need to calculate)

By using financial calculator, we obtain:

PMT = $2,583

3 0
3 years ago
Black Bear Auto Company incurred $120,000 of indirect advertising costs for its operations. The following 2017 data have been co
Alex

Answer:

a. Allocating cost using direct advertising costs

We have:

Cost allocated to New Cars = $60,000

Cost allocated to Used Cars = $48,000

Cost allocated to Parts and Service = $12,000

b. Allocating cost using Newspaper ad space

We have:

Cost allocated to New Cars = $72,000

Cost allocated to Used Cars = $36,000

Cost allocated to Parts and Service = $12,000

c. Allocating cost using Sales

We have:

Cost allocated to New Cars = $60,000

Cost allocated to Used Cars = $48,000

Cost allocated to Parts and Service = $12,000

Explanation:

Given:

                                           New Cars         Used Cars       Parts and Service

Direct advertising costs     $30,000            $24,000                $6,000

Newspaper ad space               60%                  30%                       10%

Sales                                   $250,000          $200,000            $50,000

The costs allocated to each department can now be calculated as follows:

a. Allocating cost using direct advertising costs

The indirect advertising costs can be allocated using the following formula:

Cost allocated to a department = (Direct advertising costs of the department  / Sum of direct advertising costs of the 3 departments) * Indirect advertising costs ................... (1)

Using equation (1), we have:

Cost allocated to New Cars = ($30,000 / ($30,000 + $24,000 +$6,000)) * $120,000 = $60,000

Cost allocated to Used Cars = ($24,000 / ($30,000 + $24,000 +$6,000)) * $120,000 = $48,000

Cost allocated to Parts and Service = ($6,000 / ($30,000 + $24,000 +$6,000)) * $120,000 = $12,000

b. Allocating cost using Newspaper ad space

The indirect advertising costs can be allocated using the following formula:

Cost allocated to a department = Percentage of  Newspaper ad space of the department * Indirect advertising costs ................... (2)

Using equation (2), we have:

Cost allocated to New Cars = 60% * $120,000 = $72,000

Cost allocated to Used Cars = 30% * $120,000 = $36,000

Cost allocated to Parts and Service = 10% * $120,000 = $12,000

c. Allocating cost using Sales

The indirect advertising costs can be allocated using the following formula:

Cost allocated to a department = (Sales of the department  / Sum of Sales of the 3 departments) * Indirect advertising costs ................... (3)

Using equation (3), we have:

Cost allocated to New Cars = ($250,000 / ($250,000 + $200,000 + $50,000)) * $120,000 = $60,000

Cost allocated to Used Cars = ($200,000 / ($250,000 + $200,000 + $50,000)) * $120,000  * $120,000 = $48,000

Cost allocated to Parts and Service = ($50,000 / ($250,000 + $200,000 + $50,000)) * $120,000  * $120,000 = $12,000

5 0
3 years ago
Show that the set of vectors {(−4,1,3),(5,1,6),(6,0,2)} does not span R 3 , but that it does span the subspace of R 3 consisting
Alika [10]

Answer:

The vectors does not span R3 and only span a subspace of R3 which satisfies x+13y-3z=0

Explanation:

The vectors are given as

v_1=\left[\begin{array}{c}-4&1&3\end{array}\right] \\v_2=\left[\begin{array}{c}-5&1&6\end{array}\right] \\v_3=\left[\begin{array}{c}6&0&2\end{array}\right]

Now if the vectors  would span the R^3, the rank of  the consolidated matrix will be 3 if it is not 3 this indicates that the vectors does not span the R^3.

So the matrix is given as

M=\left[\begin{array}{ccc}v_1&v_2&v_3\end{array}\right] \\M=\left[\begin{array}{ccc}-4&5&6\\1&1&0\\3&6&2\end{array}\right]\\

In order to calculate the rank, the matrix is reduced to the Row Echelon form as

\approx  \left[\begin{array}{ccc}-4&5&6\\ 0&\frac{9}{4}&\frac{3}{2}\\ 3&6&2\end{array}\right] R_2 \rightarrow R_2+\frac{R_1}{4}

\approx  \left[\begin{array}{ccc}-4&5&6\\ 0&\frac{9}{4}&\frac{3}{2}\\ 0&\frac{39}{4}&\frac{13}{2}\end{array}\right] R_3 \rightarrow R_3+\frac{3R_1}{4}\\

\approx  \left[\begin{array}{ccc}-4&5&6\\ 0&\frac{39}{4}&\frac{13}{2\\ 0&\frac{9}{4}&\frac{3}{2}}\end{array}\right] R_2\:\leftrightarrow \:R_3

\approx  \left[\begin{array}{ccc}-4&5&6\\ 0&\frac{39}{4}&\frac{13}{2}\\ 0&0&0\end{array}\right] R_3 \rightarrow R_3-\frac{3R_2}{13}\\

As the Rank is given as number of non-zero rows in the Row echelon form which are 2 so the rank is 2.

Thus this indicates that the vectors does not span R^3

<em>Now for any vector the corresponding equation is formulated by using the combined matrix which is given as  for any arbitrary vector and the coordinate as </em>

<em />v=\left[\begin{array}{c}x&y&z\end{array}\right]<em />

<em />c=\left[\begin{array}{c}c_1&c_2&c_3\end{array}\right]<em />

<em />Mc=v<em />

<em />\left[\begin{array}{ccc}-4&5&6\\1&1&0\\3&6&2\end{array}\right]\left[\begin{array}{c}c_1&c_2&c_3\end{array}\right]=\left[\begin{array}{c}x&y&z\end{array}\right]<em />

<em />M=\left[\begin{array}{ccccc}v_1&v_2&v_3& | &v\end{array}\right] \\M=\left[\begin{array}{ccccc}-4&5&6&|&x\\1&1&0&|&y\\3&6&2&|&z\end{array}\right]\\<em />

Now converting the combined matrix as

\approx  \left[\begin{array}{ccccc}-4&5&6&|&x\\ 0&\frac{9}{4}&\frac{3}{2}&|&\frac{4y+x}{4}\\ 3&6&2&|&z\end{array}\right] R_2 \rightarrow R_2+\frac{R_1}{4}\\

\approx  \left[\begin{array}{ccccc}-4&5&6&|&x\\ 0&\frac{9}{4}&\frac{3}{2}&|&\frac{4y+x}{4}\\ 0&\frac{39}{4}&\frac{13}{2}&|&\frac{4z+3x}{4}\end{array}\right] R_3 \rightarrow R_3+\frac{3R_1}{4}\\

\approx  \left[\begin{array}{ccccc}-4&5&6&|&x\\ 0&\frac{39}{4}&\frac{13}{2}&|&\frac{4z+3x}{4}\\ 0&\frac{9}{4}&\frac{3}{2}&|&\frac{4y+x}{4}\end{array}\right] R_3 \leftrightarrow R_2\\

\approx  \left[\begin{array}{ccccc}-4&5&6&|&x\\ 0&\frac{39}{4}&\frac{13}{2}&|&\frac{4z+3x}{4}\\ 0&0&0&|&\frac{13y+x-3z}{13}\end{array}\right] R_3 \rightarrow R_3-\frac{3R_2}{13}\\

From this it is seen that whatever the values of the coordinates does not effect the value of the plane with equation as

\frac{13y+x-3z}{13}=0\\or\\13y+x-3z=0\\

So it is verified that the subspace of R3 such that it satisfies x+13y-3z=0 consists of all vectors.

<em />

6 0
3 years ago
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