There are 2.74266105043 molecules in 100 grams of HCL.
The limiting reactant is chlorine (Cl2).
<u>Explanation</u>:
Limiting reactant is the amount of product formed which gets limited by the reagent without continuing it.
2 Al + 3 Cl2 ==> 2 AlCl3 represents the balanced equation.
Number of moles Al present = 34 g Al x 1 mole Al / 26.98 g
= 1.260 g moles of Al
Number of moles Cl2 present = 39 g Cl2 x 1 mole Cl2 / 35.45 g
= 1.10 g moles of Cl2
Dividing each reactant by it's coefficient in the balanced equation obtains:
1.260 moles Al / 2 = 0.63 g moles of Al
1.11 moles Cl2 / 3 = 0.36 g moles of Cl2
The reactant which produces a lesser amount of product is called as limiting reactant.
Here the Limiting reactant is Cl2.
One of the most worrisome waste products of a nuclear reactor is plutonium 239 (239Pu). This nucleus is radioactive and decays by splitting into a helium-4 nucleus and a uranium-235 nucleus (4He +... Q: One of the most worrisome waste products of a nuclear reactor is plutonium 239 (239Pu<span>).</span>
Answer: Ti is the reducing agent because it changes from 0 to +4 oxidation state.
Explanation:
- Firstly, we need to identify the reducing agent and the oxidizing agent.
- The reducing agent: is the agent that has been oxidized via losing electrons.
- The oxidizing agent: is the agent that has been reduced via gaining electrons.
- Here, Ti losses 4 electrons and its oxidation state is changed from 0 to +4 and Cl₂ gains one electron and its oxidation state is changed from 0 to -1.
- So, Ti is the reducing agent because its oxidation state changes from 0 to +4.
- Cl₂ is the oxidizing agent because its oxidation state changes from 0 to -1.
- Thus, The right answer is Ti is the reducing agent because it changes from 0 to +4 oxidation state.
Solution:
mass of the cellulose in the mixture is 0.38g
total mass of the mixture is:
3.35+0.38+8.76
=12.4g
thus the percentage of the cellulose in the mixture is:
mass of the cellulose/total mass of the mixture*100%
0.38/12.4*100%
=3%
