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Svetach [21]
3 years ago
13

How much power is required to do 180 J of work in 2.4s?​

Physics
2 answers:
Alexxandr [17]3 years ago
8 0

Answer:

75 watts

Explanation:

P= W/t

=180/2.4= 75 watts

rjkz [21]3 years ago
3 0
75
p = w / t
p = 180 / 2.4
p = 75
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The freezing point of the water is 0 C , and it equals to 273 K

Then, To convert from Kelvins degrees to Celsius degrees we use the relation

K = C + 273

Also,

C = K - 273

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Which of the following units is the SI unit of velocity? a. meter c. meter per second b. meter·second d. second per meter
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As shown in the diagram below, a rope attached to a 500.-kilogram crate is used to exert a force of 45 newtons at an angle of 65
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Horizontal component of force is given by

F_x=F\cos\theta\\\Rightarrow F_x=45\times \cos65^{\circ}\\\Rightarrow F_x=19.01\ \text{N}

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The state of matter that consists of electrically charged particles
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Suppose you take a 50gram ice cube from the freezer at an initial temperature of -20°C. How much energy would it take to complet
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Answer:

The amount of energy required is 152.68\times 10^{3}Joules

Explanation:

The energy required to convert the ice to steam is the sum of:

1) Energy required to raise the temperature of the ice from -20 to 0 degree Celsius.

2) Latent heat required to convert the ice into water.

3) Energy required to raise the temperature of water from 0 degrees to 100 degrees

4) Latent heat required to convert the water at 100 degrees to steam.

The amount of energy required in each process is as under

1) Q_1=mass\times S.heat_{ice}\times \Delta T\\\\Q_1=50\times 2.05\times 20=2050Joules

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2) Amount of heat required in phase 2 equals

Q_2=L.heat\times mass\\\\\therefore Q_{2}=334\times 50=16700Joules

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Q_3=mass\times S.heat\times \Delta T\\\\Q_1=50\times 4.186\times 100=20930Joules

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'S.heat_{water}' is specific heat of water=4.186J/^{o}C\cdot gm

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5 0
3 years ago
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