Answer:
1000 g
Explanation:
Given data:
Initial temperature of water = 45°C
Final temperature of water = 25°C
Heat released = 20 cal (4184×20 = 83680 j)
Mass of water = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of water is 4.184 j/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 25°C - 45°C
ΔT = -20°C
83680 j = m × 4.184 j/g.°C ×20°C
83680 j = m × 83.68 j/g
m = 83680 j / 83.68 j/g
m = 1000 g
One mole contains 6.02×10²³
If x mole contains 3.131×10²⁴
x = 3.131×10²⁴
-------------
6.02×10²³
x = 0.52×10²⁴¯²³
x = 0.52×10¹
x = 5.2moles....
Hope this helped...?
Answer is: formula of hydrate is CoCl₂· 6H₂O -c<span>obalt(II) chloride hexahydrate
</span>m(CoCl₂· xH₂O) = 1,62 g.
m(CoCl₂) = 0,88 g.
n(CoCl₂) = m(CoCl₂) ÷ M(CoCl₂)
n(CoCl₂) = 0,88 g ÷ 130 g/mol
n(CoCl₂) = 0,0068 mol.
m(H₂O) = 1,62 g - 0,88 g.
m(H₂O) = 0,74 g.
n(H₂O) = m(H₂O) ÷ m(H₂O)
n(H₂O) = 0,74 g ÷ 18 g/mol
n(H₂O) = 0,041 mol.
n(CoCl₂) : n(H₂O) = 0,0068 mol : 0,041 mol.
n(CoCl₂) : n(H₂O) = 1 : 6.
Answer: not to be rude but who is Miley partridge? If she is a friend then u r a kind hearted person
Explanation:
<span>an oxide of iron, magnesium, aluminum, and chromium</span>