If a mole of sodium chloride weighs approximately 58 grams, and you have 29 grams of sodium chloride, how many moles of sodium c
hloride do you have?
1 answer:
Molar mass NaCl = 58 g
Mass of solute = 29 g
number of moles: mass of solute / molar mass
n = 29 / 58
n = 0.5 moles
hope this helps!
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Answer:
0.99mol/L
Explanation:
Molarity ( M) = # of moles of solute / volume of solution (L)
Volume of Solution = 100 mL or 0.1 L
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Molarity (M) = 0.099 mol / 0.1 L = 0.99mol/ L
