Answer:
3.974 Joule
Explanation:
Diameter of ring = 7.7 cm
a = Distance from the center = d/2 = 3.85 cm = 0.0385 m
Q = Charge = 5 mC
q = Charge to move = 3.4 mC
k = Coulomb constant = 9×10⁹ Nm²/C²
Work done will be equal to Potential energy when mass is at center

∴ Work to move a tiny 3.4 mC charge from very far away to the center of the ring is 3.974 Joule
<span>The answer is fight or flight response.
The activation of the sympathetic division would prepare people for "fight or flight" response.
</span><span>The other names that are used for the fight or flight response are hyperarousal, response and the acute stress response.
There are two divisions in </span><span>autonomic nervous system, one of the division is sympathetic division and the other one is parasympathetic division.</span><span>
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If the mass and post-collision speed of block 1 is known, the momentum of the block 2 can be determined.
<h3>
What is momentum?</h3>
The momentum of an object in motion is the product of mass and speed of the object.
P = mv
<h3>Conservation of linear momentum</h3>
The principle of conservation of linear momentum states that, the sum of the initial momentum must be equal to the sum of the final momentum.

Thus, if the mass and post-collision speed of block 1 is known, the momentum of the block 2 can be determined.
Learn more about conservation of linear momentum here: brainly.com/question/7538238
Answer:
Explanation:
The two examples of contact forces are frictional force and applied force. The two examples of noncontact forces are gravitational force and magnetic force.
Had to look for the given illustration attached to this question and here is my answer. The site on the cross section provided wherein it is the most likely place for a spring would be SITE C. In the image, it is labeled sites A, B, C, and D. Hope this answers your question.