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iragen [17]
3 years ago
15

A ring of diameter 7.70 cm is fixed in place and carries a charge of 5.00 mC uniformly spread over its circumference. (a) How mu

ch work does it take to move a tiny [email protected] charged ball of mass 2.50 g from very far away to the center of the ring
Physics
2 answers:
Alekssandra [29.7K]3 years ago
6 0

Answer:

U = 3.97 J

Explanation:

GIVEN DATA:

a = 3.85 cm

q = 3.40 mc

q =5 mc

Work done to move charge to centre of the ring is equal to potential energy of the system

WORK DONE U = \frac{kqQ}{a}

                 =\frac{8.99*10^9*3.40*10^{-6} *5*10^{-6}}{3.85*10^{-2}}

U = 3.97 J

MatroZZZ [7]3 years ago
4 0

Answer:

3.974 Joule

Explanation:

Diameter of ring = 7.7 cm

a = Distance from the center = d/2 = 3.85 cm = 0.0385 m

Q = Charge = 5 mC

q = Charge to move = 3.4 mC

k = Coulomb constant = 9×10⁹ Nm²/C²

Work done will be equal to Potential energy when mass is at center

U=\frac{kQq}{a}\\\Rightarrow U=\frac{9\times 10^9\times 5\times 10^{-6}\times 3.4\times 10^{-6}}{0.0385}=3.974\ J

∴ Work to move a tiny 3.4 mC charge from very far away to the center of the ring is 3.974 Joule

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If a marathon runner averages 9.51 mi/hr, how long does it take him to run a 26.220-mile marathon. Express your answers in hours
ASHA 777 [7]

Explanation:

Speed of the marathon runner, v = 9.51 mi/hr

Distance covered by the runner, d = 26.220 mile

Let t is the time taken by the marathon runner. We know that the speed of the runner is given by total distance divided by total time taken. Mathematically, it is given by :

v=\dfrac{d}{t}

t=\dfrac{d}{v}

t=\dfrac{26.220\ mi}{9.51\ mi/hr}

t = 2.75 hours

Since, 1 hour = 60 minutes

t = 165 minutes

Since, 1 minute = 60 seconds

t = 9900 seconds

Hence, this is the required solution.

7 0
3 years ago
The use of force to move an object is <br> .
Ne4ueva [31]
The use of force to move an object is called work. This only applies if the object moves.
4 0
3 years ago
The data indicate the populations of mammals in the Florida Everglades in different years over the past two decades. The Burmese
soldier1979 [14.2K]

Answer:

C) Burmese pythons lack natural predators and can utilize a wide variety of food sources in the Everglades.

Explanation:

Due to it being an invasive specie (naturally found in South Asia), and also one of the five largest species of snakes in the world, the Burmese pythons lack natural predators in this new territories.

The Burmese viper is also an opportunistic hunter and would eat anything it can overpower, it easily made a wide range of food varieties in these swamps.

8 0
3 years ago
At Hoover Dam, the distance the water effectively falls before encountering the electric generators depends on the water levels
pashok25 [27]

Answer:

Explanation:

recall that power is energy carried out or work done per time

P=W/t

P=2*10^6*35

t=6*60=420S

W=Energy

E=2*10^6*35*360S

E=25200000000

Energy stored by water from rest is called potential energy. Since the water is falling from a height , we calculate potential energy as thus

E=M*g*h

Assume that the water intakes are effectively 175 m above the electric generators. How much water must pass through the generators to power 2 million 35-W Las Vegas light bulbs for 6.0 minutes?

M=mass of water

g=acceleration due to gravity 9.81m/s^2

h=height ,175m

25200000000=M*9.81*175

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3 0
3 years ago
: The maximum theoretical efficiency of a Carnot engine operating between reservoirs at the steam point and at room temperature
Hunter-Best [27]

Answer:

The value is   \eta  =  0.2145  or  21.45%

Explanation:

From the question we are told that

    The first reservoir is at steam point  T_s =  100^o C =  100 + 273 = 373 \ K  

    The  second reservoir is at room temperature T_r  =  20^o C = 293 \ K

Generally the  maximum theoretical efficiency of a Carnot engine  is mathematically evaluated as

     \eta  =  1- \frac{T_r}{T_s}

=>    1 - \frac{ 293}{373}

=>    \eta  =  0.2145

5 0
2 years ago
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