A ring of diameter 7.70 cm is fixed in place and carries a charge of 5.00 mC uniformly spread over its circumference. (a) How mu
2 answers:
Answer:
U = 3.97 J
Explanation:
GIVEN DATA:
a = 3.85 cm
q = 3.40 mc
q =5 mc
Work done to move charge to centre of the ring is equal to potential energy of the system
=
U = 3.97 J
Answer:
3.974 Joule
Explanation:
Diameter of ring = 7.7 cm
a = Distance from the center = d/2 = 3.85 cm = 0.0385 m
Q = Charge = 5 mC
q = Charge to move = 3.4 mC
k = Coulomb constant = 9×10⁹ Nm²/C²
Work done will be equal to Potential energy when mass is at center
∴ Work to move a tiny 3.4 mC charge from very far away to the center of the ring is 3.974 Joule
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Explanation:
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