-2y because -8x2y3 divided by xy = -8xy2, 4xy times -2y= -8xy2
Answer and explanation:
The expression P-2P+3P-4P cannot have the same values for different values of P. Let us illustrate this by substituting different values of P in the expression:
If P= 2
Substitute P=2 in the expression
2-2×2+3×2-4×2
=2-4+6-8
=-4
If P= 3
Substitute P=3 in the expression
3-2×3+3×3-4×3
=3-6+9-12
=-6
If P = 1
Substitute P=1 in the expression
1-2×1+3×1-4×1
= 1-2+3-4
= -2
If P = -2
Substitute P=1 in the expression
-2-2×-2+3×-2-4×-2
= -2+4-6+8
=4
Therefore we can see from the above that the expression has different values for different values of P
Answer:
A) 5.50x + 10y ≤ 800
B) yes
C) no
D) 80 pull buoys and 35 kick boards
Step-by-step explanation:
A) The sum of costs must not exceed the budget:
5.50x +10.00y ≤ 800
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B) 5.50(0) +10.00(50) = 500 ≤ 800 . . . . . yes, the coach could buy these
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C) 5.50(125) +10.00(25) = 937.50 > 800 . . . no, they cost too much
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D) The point (80, 35) is in the solution space. The coach could buy 80 pull buoys and 35 kick boards.
since ΔQRS similar to ΔQRP, then
SR/QR = QR/PR
x/12 = 12/(3.5+x)
x(3.5+x) = 12²
x² + 3.5x = 144
x² + 3.5x - 144 = 0
approximately 10.38
Answer:
//The class called "Solution" is declared
public class Solution {
//Main method which signify the beginning of program execution
public static void main(String[] args) {
//myInt variable of type Integer is declared
Integer myInt;
// An object of type Integer is declared with initial value of 1
Integer newInt = new Integer(1);
// The value of the new declared and assigned object is displayed to the user
System.out.println(newInt);
// The new declared object is assigned to the reference variable myInt
myInt = newInt;
// The value of myInt is displayed to the user
System.out.println(myInt);
}
}
Step-by-step explanation:
