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2 years ago

Which has more momentum, a heavy truck moving at 30 miles per hour or a light truck moving at 30 miles per hour?

Physics

2 answers:

denis-greek [22]2 years ago

8 0

Answer: The heavy truck

Explanation: Momentum is defined as the amount of movement.

It can be written as P = m*v

Where P is the momentum, m is the mass of the object and v is the velocity.

So you can see that if the mass increases, also does the momentum, so if both trucks move at the same velocity, then the truck with the bigger mas will have a bigger momentum.

Then the correct answer is the heavy truck

valentina_108 [34]2 years ago

7 0

A heavy truck moving a 30 mph. It has more mass.

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A particle starts from rest and is acted on by a net force that does work at a rate that is proportional to the time t. The spee

vova2212 [387]

The speed of the particle is proportional to = √t

Work = the change in kinetic energy = 1/2 mv2

If work is proportional to time

W = t

1/2 mv2 = t

v2 = t

v (speed) = √t

Speed is the time rate at which an object is shifting along a path, even as speed is the fee and route of an item's movement. Positioned every other manner, speed is a scalar value, even as pace is a vector.

Velocity (or price, r) is a scalar quantity that measures the gap traveled (d) over the alternate in time (Δt), represented via the equation r = d/Δt.

The Italian physicist Galileo Galilei is credited with being the first to measure speed by considering the gap blanketed and the time it takes. Galileo described pace as the gap covered in line with unit of time.

Learn more about speed here:- brainly.com/question/13943409

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8 0

1 year ago

Future space rockets might propel themselves by firing laser beams, rather than exhaust gases, out the back. The acceleration wo

Nina [5.8K]

Answer:

Acceleration = 0.0282 m/s^2

Distance = 13.98 * 10^12 m

Explanation:

we will apply the energy theorem

work done = ΔK.E ( change in Kinetic energy ) ---- ( 1 )

where :

work done = p * t

= 15 * 10^6 watts * ( 1 year ) = 473040000 * 10^6 J

( note : convert 1 year to seconds )

and ΔK.E = 1/2 mVf^2 given ; m = 1200 kg and initial V = 0

back to equation 1

473040000 * 10^6 = 1/2 mv^2

Vf^2 = 2(473040000 * 10^6 ) / 1200

∴ Vf = 887918.92 m/s

i) Determine how fast the rocket is ( acceleration of the rocket )

a = Vf / t

= 887918.92 / ( 1 year )

= 0.0282 m/s^2

ii) determine distance travelled by rocket

Vf^2 - Vi^2 = 2as

Vi = 0

hence ; Vf^2 = 2as

s ( distance ) = Vf^2 / ( 2a )

= ( 887918.92 )^2 / ( 2 * 0.0282 )

= 13.98 * 10^12 m

8 0

2 years ago

Listed following are the names and mirror diameters for six of the world’s greatest reflecting telescopes used to gather visible

ziro4ka [17]

Answer:

Large binocular telescope, Keck 1 telescope, Hobby-Ebberly telescope, Subaru telescope, Gemini North telescope, Magellan 2 telescope

Explanation:

How much light a telescope can collect depends on its diameter, since in a bigger area more photons will be collected.

Remember that in a circle the area is defined as:

$A = \pi r^{2}$ (1)

Where A is the area and r is its radius.

However, the radius can be determined by means of its diameter.

$d = 2r$

$r = \frac{d}{2}$ (1)

Where d is its diameter.

An example of this is when a person is collecting raindrops with a bucket and with a cup. Since the bucket has a bigger area than the cup, it will collect more raindrops by unit of time. In this scenario the raindrops represent the photons.

To determine the light collecting area of each telescope, equation 2 will be replaced in equation 1.

$A = \pi (\frac{d}{2})^{2}$ (3)