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katrin [286]
3 years ago
11

How does the momentum change if the mass of an object is doubled?

Physics
1 answer:
seraphim [82]3 years ago
7 0

Answer:

if you double the mass or velocity you double the momentum.

Explanation:

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A pelican flying along a horizontal path drops a fish from a height of 5.4 m. The fish travels 8.0 m horizontally before it hits
umka2103 [35]

Answer:

Speed, Vfx = 7.619 m/s

Explanation:

Vertical distance, Dx = 5.4m

Horizontal distance, Dy = 8m

Acceleration due to gravity, g = 9.8m/s²

Initial speed, Vix = 0m/s²

To find the speed, we would use the second equation of motion to find the time, t;

Dx = Vixt + ½gt²

Substituting into the equation, we have;

5.4 = 0(t) + ½(9.8)*t²

5.4 =  0 + 4.9t²

Rearranging the equation, we have;

4.9t² = 5.4

t² = 5.4/4.9

t² = 1.1020

Taking the square root of both sides;

t = 1.050 secs.

For the speed;

Dy = Vfxt

Vfx = Dy/t

Vfx = 8/1.050

Vfx = 7.619 m/s

<em>Therefore, the speed of the pelican is 7.619 m/s</em>

6 0
3 years ago
A stone of mass m is thrown upwards at an angle φ. The moment the stone leaves your hand it has an acceleration (friction is neg
Lelechka [254]
The correct answer is:

= g

Explanation:

When the object leaves the hand it has a force acted on it mainly it’s weight.
5 0
3 years ago
Why are lanthanum and actinium at the bottom of the periodic table?
7nadin3 [17]
The periodic table is organized in a way in which trends with certain things such as ionization energy or atomic radius would "work out". It also have increasing atomic mass.

It's also organized to tell you the electron and proton of each element, least to greatest. (the atomic number) Example: Chlorine has 17 protons and 17 e-
(Left to right)
(Top to bottom)

Lanthanum and actinium play the role of being in the bottom because of their large atomic radius and having many protons/electrons.
They're also in the F block for electron configuration.

8 0
3 years ago
Design a modified priority encoder that receives an 8-bit input, A7:0and produces a 3-bit output, Y2:0. Y indicates the most sig
cupoosta [38]

Answer:

Explanation:

The first image that I attached to this solution is the diagram of a truth table for an 8 to 3 bit encoder.

The second image  gives a sketch of the schematic.

The Boolean expression for the priority encoder including its zero inputs is defined in the third image attached.

Below is a snippet of the code for an 8 to 3 bit Priority encoder:

library IEEE;

use IEEE.STD_LOGIC_1164.all;

entity encoder8_3 is

   port(

       din : in STD_LOGIC_VECTOR(7 downto 0);

       dout : out STD_LOGIC_VECTOR(2 downto 0)

        );

end encoder8_3;

architecture encoder8_3_arc of encoder8_3 is

begin

   dout <= "000" when (din="10000000") else

           "001" when (din="01000000") else

           "010" when (din="00100000") else

           "011" when (din="00010000") else

           "100" when (din="00001000") else

           "101" when (din="00000100") else

           "110" when (din="00000010") else

           "111";

end encoder8_3_arc;

3 0
3 years ago
HELP PLS RIGHT ANSWER GETS BRAINLIEST!!!!
mr Goodwill [35]

Answer:

<em><u>♧</u></em><em><u> </u></em><em><u>Write</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>correct</u></em><em><u> </u></em><em><u>abbreviation</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>each</u></em><em><u> </u></em><em><u>metric</u></em><em><u> </u></em><em><u>unit</u></em><em><u>.</u></em>

  1. kg
  2. m
  3. g
  4. mL
  5. mm
  6. L
  7. km
  8. cm
  9. mg

<em><u>♧</u></em><em><u> </u></em><em><u>Try</u></em><em><u> </u></em><em><u>these</u></em><em><u> </u></em><em><u>conversions</u></em><em><u>,</u></em><em><u> </u></em><em><u>using</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>ladder</u></em><em><u> </u></em><em><u>method</u></em><em><u>.</u></em>

  1. 2 g
  2. 104000 m
  3. 4.8 m
  4. 5600 g
  5. 0.8 cm
  6. 5000 mL
  7. 0.198 kg
  8. 0.075 L
  9. 0.5 m
  10. 560 cm
  11. 160 mm
  12. 2.5 km
  13. 65000 mg
  14. 63 mm
  15. 0.12 g

<em><u>♧</u></em><em><u> </u></em><em><u>Compare</u></em><em><u> </u></em><em><u>using</u></em><em><u> </u></em><em><u><</u></em><em><u>,</u></em><em><u> </u></em><em><u>></u></em><em><u>,</u></em><em><u> </u></em><em><u>or</u></em><em><u> </u></em><em><u>=</u></em><em><u>.</u></em>

16. <

17. >

18. =

19. =

20. <

21. >

8 0
3 years ago
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