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musickatia [10]
3 years ago
6

Habiba and selehadin have measured the voltage across a resistor to be 5.26V and the current flowing through in to be 0.41A they

work out the resistance .
habiba says the resistance is 12.8 ohms .selehadin disagrees and says that is 13 ohm .

who is correct?.​
Physics
1 answer:
slavikrds [6]3 years ago
4 0

Considering the definitipn of current, voltage, power, and Ohm's law,

  • <u><em>Current</em></u>

The flow of electricity through an object, such as a wire, is known as current (I). Its unit of measurement is amps (A). So current is a measure of the speed at which the load passes through a given reference point in a specified direction.

  • <u><em>Voltage</em></u>

The conductive force (electrical pressure) behind the flow of a current is known as voltage and is measured in volts (V) (voltage can also be referred to as the potential difference or electromotive force). That is, voltage is a measure of the work required to move a charge from one point to another.

  • <em><u>Resistance</u></em>

Resistance (R) refers to the resistance or opposition that an element has to the passage of electric current. It is represented by the symbol Ω and indicates the resistance that an element offers to the passage of electricity.

This means that the greater the resistance to the passage of current, the lower the intensity or amount of electricity that passes through this conductor.

The resistance that is measured in ohms.

  • <u><em>Ohm's law</em></u>

Ohm's law indicates that the current through a circuit is directly proportional to its voltage or voltage and inversely proportional to the resistance it presents.

Mathematically, Watt's law is expressed:

I=\frac{V}{R}

So if you want to find resistance, the expression for its calculation is:

R=\frac{V}{I}

  • <u><em>This case</em></u>

In this case, you know:

  1. V= 5.26 V
  2. I= 0.41 A

Replacing:

R=\frac{5.26 V}{0.41 A}

Solving:

<u><em>R= 12.8 ohms</em></u>

<u><em /></u>

Habiba is right. The resistance is 12.8 ohms.

Learn more:

  • brainly.com/question/23205779?referrer=searchResults
  • brainly.com/question/13485930?referrer=searchResults
  • brainly.com/question/9813227?referrer=searchResults
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Answer:

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(a) The velocity of the ball before it hits the floor is given by:

v=\sqrt{2gh}        (1)

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v=\sqrt{2(9.8m/s^2)(1.50m)}=5.42\frac{m}{s}

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(b) To calculate the velocity of the ball, after it leaves the floor, you use the information of the maximum height reached by the ball after it leaves the floor.

You use the following formula:

h_{max}=\frac{v_o^2}{2g}       (2)

vo: velocity of the ball where it starts its motion upward

You solve for vo and replace the values of the parameters:

v_o=\sqrt{2gh_{max}}=\sqrt{2(9.8m/s^2)(1.10m)}=4.64\frac{m}{s}

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a=\frac{\Delta v}{\Delta t}=\frac{v_o-v}{3.50*10^{-3}s}=\frac{4.64m/s-(-5.42m)/s}{3.50*10^{-3}s}=2874.285\frac{m}{s^2}

a=\frac{\Delta v}{\Delta t}=\frac{v_o-v}{3.50*10^{-3}s}=\frac{4.64m/s-5.42m/s}{3.50*10^{-3}s}=-222.85\frac{m}{s^2}

The acceleration of the ball is 2874.28/s^2

(d) The compression of the ball is:

\Deta y=\frac{v^2}{2(a)}=\frac{(5.42m/s)^2}{2(2874.28m/s^2)}=5.11*10^{-3}m

THe compression of the ball when it strikes the floor is 5.11*10^-3m

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P = W/t
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The central force acting on the electron as it revolves in a circular orbit is calculated as follows;

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now we have

v = \sqrt{\frac{(6.67 \times 10^{-11})(5.98 \times 10^{24})}{6.37 \times 10^6 + 9.0 \times 10^5}}

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