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klio [65]
3 years ago
15

Use the table of electric force between objects in two different interactions to answer the question. Interaction Charge on Obje

ct 1 (C) Charge on Object 2 (C) Amount of Force A +1 -2 weak B +1 +2 strong Which conclusion about the interactions is correct? (1 point) O The objects in interaction A are farther apart than in interaction B. O The objects in interaction A are smaller than in interaction B O Positive charges are stronger than negative charges. O Repulsive forces are stronger than attractive forces. Type here to search​
Physics
1 answer:
forsale [732]3 years ago
6 0

Answer:?that’s a lot

Explanation:

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At a certain point in space, there is a potential of 800 V relative to zero. What is the potential energy of the system when a +
sammy [17]

To solve this problem we will apply the concepts related to electric potential and electric potential energy. By definition we know that the electric potential is determined under the function:

V = \frac{k_e q}{r}

k_e = Coulomb's constant

q = Charge

r = Radius

At the same time

U = \frac{k_e q_1q_2}{r}

The values of variables are the same, then if we replace in a single equation we have this expression,

U  = Vq

If we replace the values, we have finally that the charge is,

V = 800V

q = 1\mu C

U = (800V)(1*10^{-6}C)

U = 8*10^{-4}J

Therefore the potential energy of the system is 8*10^{-4} J

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3 years ago
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Cleats Chicks Bits and Bollards. Hope this helps
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4 years ago
A 60.0-kg man stands at one end of a 20.0-kg uniform 10.0-m long board. How far from the man is the center of mass of the man-bo
timama [110]

Answer:

x=1.25m

Explanation:

The <em>Center of mass </em>of the system is defined as the point where whole mass of the body is appeared to be  concentrated.

The center of mass of the system is given by

         x=  \frac{m1x1+m2x2}{m1+m2}      

where m1 is mass of man =60 kg

           m2 mass of board =20 kg

let the man be at the origin  x1 =0 , x2 =5m

by substituting in above formula

x =\frac{(60*0)+(20*5)}{60+20} = \frac{100}{80} =1.25 m

x=1.25m

So the center of mass of the system is at 1.25 m from man.

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4 years ago
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If a model ship is scaled to the ratio of 1:1,200, what size is the real ship
Ipatiy [6.2K]
The answer I had got was C x
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A force of 19 newtons is applied on a cart of 2 kilograms, and it experiences a frictional force of 1.7 newtons. What is the acc
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A= f/m

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