Question

100 POINTS PLEASE HELP

Answer 1

Answer:

Explanation:

Spilling the force of 60N on the rope at an angle θ in x-y direction:

fx = Fcosθ = 60cosθ

fy = Fsinθ = 60sinθ

cosθ and sinθ both vary from 0 to 1 between 0° to 90° but they go in opposite direction:

cos0° = 1 and cos90° = 0

sin0° = 0 and sin90° = 1

sin45° = cos45° = 0.7071

When θ increases from 0° to 90°,

θ=0°, fx = 60cos0° = 60N, fy = 60sin0° = 0N

θ=90°, fx = 60cos90° = 0N, fy = 60sin90° = 60N

θ=45°, fx = 60cos45° = fy = 60sin45° = 42.43N

Answer 2

Answer:

Explanation:

vector force F = 60N = Fx + Fy

where Fx = 60 cos(theta) and Fy = 60 sin(theta)

cos decreases from 1 to 0 from 0deg to 90 deg

sin increases from 0 to 1 from 0deg to 90deg

so Fx=60N and Fy=0N when theta=0deg

Fx=60cos45deg and Fy=60sin45deg when theta=45deg

Fx=0N and Fy=60N when theta=90deg