Choice C.
That's when convection stops.
Since the tower base is square with a side length of 125 m,
Therefore,

Square root of 31250 = 176.776953 (Diameter)
, so this is the diameter of the cylinder to enclose it, and radius, r = 88.38834765 m and height, h = 324 m.
The volume of cylinder,

Thus, the mass of the air in the cylinder,

Hence, the mass of the air in the cylinder is this more than the mass of the tower.
Please look at the attached awesome drawing.
Both answers are there.
Answer: Yes, the answer is D.
Explanation: Sound waves are transverse waves, which are the fastest type of wave and can travel (almost) any medium with the exception of a few natural elements.
Given the particle's acceleration is

with initial velocity

and starting at the origin, so that

you can compute the velocity and position functions by applying the fundamental theorem of calculus:


We have
• velocity at time <em>t</em> :

• position at time <em>t</em> :
