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amm1812
3 years ago
11

At high temperatures, steam decomposes into its elements according to the following equation.

Chemistry
2 answers:
Nata [24]3 years ago
8 0
_Award brainliest if helped!
20% steam converted, 0.8atm of steam remains
Converted to 0.2atm H2(g) and 0.1atm O2(g)
Partial Pressure of
H2O(g) =0.8/1.1 =0.727atm
H2(g) = 0.2/1.1 =0.181atm
O2(g) = 0.1/1.1 = 0.091atm
lina2011 [118]3 years ago
5 0

Answer:

Explanation:

how

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Three metal spoons are on table. They are at room temperature. If the three spoons touch.
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3 years ago
Read 2 more answers
Find the actual yield when the theatrical yield is 1.09g and percent yield is 90%.​
ioda
Actual yield/Theoretical yield *100= Percentage yield. So Actual yield = Percentage yield*Theoretical yield.
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Actual yield: 0.98 g
3 0
2 years ago
In the reaction A + B C, doubling the concentration of A doubles the reaction rate and doubling the concentration of B does not
frutty [35]

Answer:

rate = k[A]

Explanation:

The equation that relate reaction rate with reactant concentrations is known as the rate law.

for a reaction:

  • A + B  → C

the rate law can be expressed as:  

  • Rate = k[A]ᵃ[B]ᵇ

The proportionality constant, k, is known as the rate constant, the powers a and b is the reaction order with respect to reactants A and B, respectively.

for this reaction doubling the concentration of A doubles the reaction rate that means

Rate₂ = 2 *Rate₁     and     [A]₂ = 2 [A]₁

  • Rate₁ = k[A]₁ᵃ[B]ᵇ    → eq. 1
  • Rate₂ = k[A]₂ᵃ[B]ᵇ    → eq. 2

Dividing eq. 2 by eq. 1 one can get

  • (Rate₂ / Rate₁) = (k [A]₂ᵃ[B]ᵇ) / (k[A]₁ᵃ[B]ᵇ)

using

  • Rate₂ = 2 *Rate₁     and     [A]₂ = 2 [A]₁

∴ (2 Rate₁ / Rate₁) = ( k [2]ᵃ[B]ᵇ) / (k[1]ᵃ[B]ᵇ)

  • (2) = (2)ᵃ
  • taking log of both sides
  • log (2) = a Log (2)
  • 0.693 = a * 0.693
  • a =1  

∴ order of reaction with respect to A is first (=1)        →     (1)

Doubling the concentration of B does not affect the reaction rate.

that means

Rate₂ = Rate₁     and     [B]₂ = 2 [B]₁

  • Rate₁ = k[A]ᵃ[B]₁ᵇ    → eq. 1
  • Rate₂ = k[A]ᵃ[B]₂ᵇ    → eq. 2

Dividing eq. 2 by eq. 1 one can get

  • (Rate₂ / Rate₁) = (k [A]ᵃ[B]₂ᵇ) / (k[A]ᵃ[B]₁ᵇ)

using

  • Rate₂ = Rate₁     and   [B]₂ = 2 [B]₁

∴ (Rate₁ / Rate₁) = ( k [A]ᵃ[2]ᵇ) / (k[A]ᵃ[1]ᵇ)

  • (1) = (2)ᵇ
  • taking log of both sides
  • log (1) = b Log (2)
  • 0 = 0.693 * b
  • b = 0

∴ order of reaction with respect to B is zero         →     (2)

So, from 1 and 2  the right choice is rate = k[A]¹[B]⁰= k[A]

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2 years ago
2. Solid sodium reacts with gaseous chlorine to produce sodium chloride.
stich3 [128]
2Na (s) + Cl2 (g) = 2NaCl (s)
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