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PIT_PIT [208]
3 years ago
5

What is the order of increasing rate of eusion for the following gases, Ar, CO2, H2, N2?

Chemistry
1 answer:
AVprozaik [17]3 years ago
8 0

Answer:

H2 > N2 > Ar > CO2

Explanation:

Graham's law explains why some gases efuse faster than others. This is due to the difference i their molar mass. Generally; The rate of effusion of gaseous substances is inversely proportional to the square rot of its molar mass.

This means gases with low molar masses would have higher efusion rate compared to gases with higher molar masses.

So now we just need to compare the molar masses of the various gases;

Ar - 39.95

CO2 - 44.01

H2 - 2

N2 - 28.01

To obtain the order in increasing rate, we have to order the gases in decreasing molar mass. This order of increasing rate is given as;

H2 > N2 > Ar > CO2

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uh yeah I think so technically

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P1 = 760 torr

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V2 = ?

applying Boyle's Law

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V2 = 760 torr * 30 mL / 1520 torr

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The liter is used to measure _____.<br><br> weight<br> mass<br> volume<br> length
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the answer to your question is

volume

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Two iron rods are placed horizontally, touching end-to-end. One end of one rod is heated. After some time, the other rod also fe
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Electrons conducted heat

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Consider the two rods to be a singular rod, since they touch:

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You need to prepare 1 L of the citric acid/citrate buffer. You have chosen to use Method 1 (see lab presentation). Calculate the
prisoha [69]

Answer:

3.11 is the pH of the buffer

Explanation:

The pH of a buffer is obtained using H-H equation:

pH = pKa + log [Conjugate base] / [Weak acid]

<em>Where pH is the pH of the buffer, pKa = -log Ka = 3.14 for the citric buffer and [] could be taken as the moles of each species.</em>

The citric acid,HX (Weak acid), reacts with NaOH to produce sodium citrate, NaX (weak base) and water:

HX + NaOH → H2O + NaX

That means the moles of NaOH added = Moles of sodium citrate produced

And the resulitng moles of HX = Initial moles - Moles NaOH added

<em>Moles HX and NaX:</em>

Moles NaOH = 0.100L * (0.65mol / L) = 0.065 moles NaOH = Moles NaX

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Replacing in H-H equation:

pH = 3.14 + log [0.065mol] / [0.070mol]

pH = 3.11 is the pH of the buffer

8 0
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