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ser-zykov [4K]
4 years ago
14

You want to put $8,000 in a simple interest account. It has a 2% annual interest rate. How long must you invest that money to ea

rn $400 in interest?
Mathematics
2 answers:
Aleks [24]4 years ago
7 0
Simple interest = starting amount x time (in years) x rate
8000(0.02)(t)=400
160t= 400
t= 400/160 =2.5 Years
2.5 years will be 2 years and 6 months
vodomira [7]4 years ago
3 0
I = prt is the formula for simple interest
400 = 8000* .02 * t
400 = 160 * t
2.5 = t
2.5 years to earn $400 interest
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What is the surface area of a tank that has a length of 30 feet, a width of 15 feet?
Lady bird [3.3K]

Answer:

450

Step-by-step explanation:

Multiply the length (30) by the width (15)

30x15=450

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3 years ago
Ariana's family took a road trip to the Grand Canyon. Ariana fell asleep 65% of the way through the trip. If Ariana fell asleep
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650 is 65% of 1000 miles

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4 years ago
What is the variable in this expression?<br> 4b + 2b + 1⁄4
Shtirlitz [24]

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Step-by-step explanation:

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3 years ago
The lengths of text messages are normally distributed with a population standard deviation of 6 characters and an unknown popula
ryzh [129]

Answer:

The 80% confidence interval for the population mean is between 28.32 characters and 31.68 characters.

Step-by-step explanation:

We have the standard deviation for the population, so we can use the normal distribution. If we had the standard deviation for the sample, we would have to use the t-distribution.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.8}{2} = 0.1

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.5 = 0.9, so z = 1.282

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.282*\frac{6}{\sqrt{21}} = 1.68

The lower end of the interval is the sample mean subtracted by M. So it is 30 - 1.68 = 28.32 characters.

The upper end of the interval is the sample mean added to M. So it is 30 + 1.68 = 31.68 characters.

The 80% confidence interval for the population mean is between 28.32 characters and 31.68 characters.

6 0
3 years ago
Find the selling price of a sled with an original price of $99.50 and a 95% markup
neonofarm [45]
99.50 times .95
94.53
99.50+94.53
194.03
Answer:
$194.03
6 0
4 years ago
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