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ohaa [14]
3 years ago
12

The sprinter ran 110 m in 11 seconds. What was her average speed in m/s?

Physics
2 answers:
Tanya [424]3 years ago
5 0

Answer:

10 m/s

Explanation:

110/11=10

Sunny_sXe [5.5K]3 years ago
5 0

Answer:

10 m/s

Explanation:

110/11=  10 m/s

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How is high-speed internet typically transmitted around the world? over telephone wires b. through fiber optic cables c. beamed wirelessly to homes d via satellites​

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The idea that large fibers in the sensory nerves can prevent impulses from reaching the brain and thus prevent the sensation of
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Gate control theory of pain

Explanation:

The gate control theory of pain sates that non-painful input closes the nerve gates to painful input, which prevents pain sensation from traveling to the central nervous system (brain).

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3 years ago
The energy flow to the earth from sunlight is about 2 1.4 kW>m . (a) Find the maximum values of the electric and mag- netic f
solmaris [256]

Complete question is;

The energy flow to the earth from sunlight is about 1.4kW/m²

(a) Find the maximum values of the electric and magnetic fields for a sinusoidal wave of this intensity.

(b) The distance from the earth to the sun is about 1.5 × 10^(11) m. Find the total power radiated by the sun.

Answer:

A) E_max ≈ 1026 V/m

B_max = 3.46 × 10^(-6) T

B) P = 3.95 × 10^(26) W

Explanation:

We are given;

Intensity; I = 1.4kW/m² = 1400 W/m²

Formula for maximum value of electric field in relation to intensity is given as;

E_max = √(2I/(ε_o•c))

Where;

ε_o is electric constant = 8.85 × 10^(-12) C²/N.m²

c is speed of light = 3 × 10^(8) m/s

Thus;

E_max = √(2 × 1400)/(8.85 × 10^(-12) × 3 × 10^(8)))

E_max ≈ 1026 V/m

Formula for maximum magnetic field is;

B_max = E_max/c

B_max = 1026/(3 × 10^(8))

B_max = 3.46 × 10^(-6) T

Formula for the total power is;

P = IA

Where;

A is area = 4πr²

We are given;

Radius; r = 1.5 × 10^(11) m

A = 4π × (1.5 × 10^(11))² = 2.82 × 10^(23) m²

P = 1400 × 2.82 × 10^(23)

P = 3.95 × 10^(26) W

5 0
3 years ago
A horizontal pull A pulls two wagons over a horizontal frictionless floor, the first wagon is 500N, the second is 2000 N. The te
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<span>The force will be zero if the wagons are moving at a constant speed (i.e. not accelerating), as there is no frictional force to overcome. If the wagons are accelerating, the force will be proportional to the acceleration, and 20% of the force applied by A.</span>
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4 years ago
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