Frictional force between the object and the floor=5 N
Explanation:
power= 50 W
velocity= 10 m/s
power= force * velocity
50=F * 10
F=50/10
F=5 N
Thus the force of friction= 5 N
Newton's Third Law states that for every action there is an opposite and equal reaction:
If the gravitational force of the Earth on the Moon is F then the gravitational force of the Moon on the Earth is also F
Answer:
2.48 m/s
Explanation:
We can use the kinematic equation,
s = ut +½at²
Where
s = displacement
u = initial velocity
t = time taken
a = acceleration
Using the equation in vertical direction,
321 = 0×t +½×g×t², u = 0 because initial vertical velocity is 0
We get t = 8.01 s
Using the equation in the horizontal direction,
52 = u×8.01 +½×0×(8.01)²,. a = 0 because no unbalanced force act on object in that direction
So u = 2.48 m/s
The moment of inertia is the rotational analog of mass, and it is given by
the product of mass and the square of the distance from the axis.
- The moment of inertia changes as the position of the weight is changed, which indicates that; statement is incorrect
Reasons:
The weight on each arm that have adjustable positions can be considered as point masses.
The moment of inertia of a point mass is <em>I</em> = m·r²
Where;
m = The mass of the weight
r = The distance (position) from the center to which the weight is adjusted
Therefore;
The moment of inertia, <em>I </em>∝ r²
Which gives;
Doubling the distance from the center of rotation, increases the moment of inertia by factor of 4.
Therefore, the statement contradicts the relationship between the radius of rotation and moment of inertia.
Learn more about moment of inertia here:
brainly.com/question/4454769
Answer:
C) 7.35*10⁶ N/C radially outward
Explanation:
- If we apply the Gauss'law, to a spherical gaussian surface with radius r=7 cm, due to the symmetry, the electric field must be normal to the surface, and equal at all points along it.
- So, we can write the following equation:
- As the electric field must be zero inside the conducting spherical shell, this means that the charge enclosed by a spherical gaussian surface of a radius between 4 and 5 cm, must be zero too.
- So, the +8 μC charge of the solid conducting sphere of radius 2cm, must be compensated by an equal and opposite charge on the inner surface of the conducting shell of total charge -4 μC.
- So, on the outer surface of the shell there must be a charge that be the difference between them:
- Replacing in (1) A = 4*π*ε₀, and Qenc = +4 μC, we can find the value of E, as follows:
- As the charge that produces this electric field is positive, and the electric field has the same direction as the one taken by a positive test charge under the influence of this field, the direction of the field is radially outward, away from the positive charge.