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denis-greek [22]

3 years ago

12

What does wave speed have to do with all SONAR AND RADAR technologies?

2 answers:

posledela3 years ago

8 0

Answer:

1) Radar uses radio waves, which are a type of electromagnetic energy. Sonar uses the echo principle by sending out sound waves underwater or through the human body to locate objects. Sound waves are a type of acoustic energy. Because of the different type of energy used in radar and sonar, each has its own applications.

2)Radar systems operate using radio waves primarily in air, while sonar systems operate using sound waves primarily in water (Minkoff, 1991). Despite the difference in medium, similarities in the principles of radar and sonar can frequently result in technological convergence.

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Explanation:

Elena L [17]3 years ago

4 0

Explanation:

1) Radar uses radio waves, which are a type of electromagnetic energy. Sonar uses the echo principle by sending out sound waves underwater or through the human body to locate objects. Sound waves are a type of acoustic energy. Because of the different type of energy used in radar and sonar, each has its own applications.

2)Radar systems operate using radio waves primarily in air, while sonar systems operate using sound waves primarily in water (Minkoff, 1991). Despite the difference in medium, similarities in the principles of radar and sonar can frequently result in technological convergence.

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What does a velocity measurement include that a speed measurement does not? A: Time B:direction C:distance D: acceleration

andrew-mc [135]

Answer:

B. Direction

Explanation:

Speed is a scalar quantity and doesn't keep track of direction : Velocity is a vector quantity and is direction aware.

8 0

2 years ago

A screen is placed a distance dd to the right of an object. A converging lens with focal length ff is placed between the object

Elina [12.6K]

Answer:

2f

Explanation:

The formula for the object - image relationship of thin lens is given as;

1/s + 1/s' = 1/f

Where;

s is object distance from lens

s' is the image distance from the lens

f is the focal length of the lens

Total distance of the object and image from the lens is given as;

d = s + s'

We earlier said that; 1/s + 1/s' = 1/f

Making s' the subject, we have;

s' = sf/(s - f)

Since d = s + s'

Thus;

d = s + (sf/(s - f))

Expanding this, we have;

d = s²/(s - f)

The derivative of this with respect to d gives;

d(d(s))/ds = (2s/(s - f)) - s²/(s - f)²

Equating to zero, we have;

(2s/(s - f)) - s²/(s - f)² = 0

(2s/(s - f)) = s²/(s - f)²

Thus;

2s = s²/(s - f)

s² = 2s(s - f)

s² = 2s² - 2sf

2s² - s² = 2sf

s² = 2sf

s = 2f

8 0

3 years ago

A cube that has a volume of 1.00 m³ contains N distinguishable particles.

grandymaker [24]

Answer:

1 P = 0.5

2 P = 0.3

3 P = 0.01

Explanation:

The probability formula is

$P =V^N$

Where P is the probability V is the volume while N is the number of distinguishing particles

So for N = 1 and $V = 0.500m^3$

$P = (0.500m^3)^1\\$

= 0.5

For N = 1 and $V = 0.300m^3$

$P = (0.300m^3)^1$

= 0.3

For N = 1 and $V = 0.0100m^3$

$P =(0.0100m^3)^1$

= 0.01

6 0

3 years ago

A TV set is pushed a distance of 2 m with a force of 20 N how much work is done on the set

vladimir2022 [97]

Answer:

40 J

Explanation:

8 0

3 years ago

A freight train rolls along a track with considerable momentum. If it were to roll at the same speed but had twice as much mass,

fomenos

Answer:

The momentum would be doubled

Explanation:

The magnitude of the momentum of the freight train is given by:

$p=mv$

where

m is the mass of the train

v is its speed

In this problem, we have that the speed of the train is unchanged, while the mass of the train is doubled:

$m'=2m$

therefore, the new momentum is

$p'=m'v=(2m)v=2(mv)=2p$

so, the momentum has also doubled.

7 0

3 years ago