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Marysya12 [62]
4 years ago
7

Geneva says that the only thing people need to hear the sounds around them is a vibrating object. do you agree with her? explain

your answer.
Physics
2 answers:
kondaur [170]4 years ago
6 0
Sound is transmitted from one location to another through the sound waves. It is a pattern of disturbance and travels through different media (water, air, or any vibrating objects). With what has been written in the last two sentences, I think I might agree with Geneva given that without the vibrating objects, sound waves will not be able to travel. 
puteri [66]4 years ago
3 0

Answer:

No, I do not agree with her. In order for sounds to be heard, the sound wave produced by a vibrating object needs to travel from the vibrating object to the ear through a medium.

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3 years ago
A ball is thrown upward with a speed of 28.2 m/s.A. What is its maximum height?B. How long is the ball in the air?C. When does t
Ede4ka [16]

Answer:

(A) The maximum height of the ball is 40.57 m

(B) Time spent by the ball on air is 5.76 s

(C) at 33.23 m the speed will be 12 m/s

Explanation:

Given;

initial velocity of the ball, u = 28.2 m/s

(A) The maximum height

At maximum height, the final velocity, v = 0

v² = u² -2gh

u² = 2gh

h = \frac{u^2}{2g}\\\\h = \frac{(28.2)^2}{2*9.8}\\\\h = 40.57 \ m

(B) Time spent by the ball on air

Time of flight = Time to reach maximum height + time to hit ground.

Time to reach maximum height = time to hit ground.

Time to reach maximum height  is given by;

v = u - gt

u = gt

t = \frac{u}{g}

Time of flight, T = 2t

T = \frac{2u}{g}\\\\ T = \frac{2*28.2}{9.8}\\\\ T = 5.76 \ s

(C) the position of the ball at 12 m/s

As the ball moves upwards, the speed drops, then the height of the ball when the speed drops to 12m/s will be calculated by applying the equation below.

v² = u² - 2gh

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12² - 28.2² = - 2(9.8)h

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h = 651.24 / 19.6

h = 33.23 m

Thus, at 33.23 m the speed will be 12 m/s

6 0
3 years ago
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