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Valentin [98]
3 years ago
9

3 characteristics of physical change

Physics
2 answers:
Nady [450]3 years ago
5 0

Answer:

Explanation:

A physical property is a characteristic of matter that is not associated with a change in its chemical composition. Familiar examples of physical properties include density, color, hardness, melting and boiling points, and electrical conductivity.

Mashutka [201]3 years ago
5 0

Answer: it involves a change in physical properties, such as melting, condensing, evaporating, change of color, shape, size, volume an density

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Jobisdone [24]
 Air pollution<span> is a major environmental </span>risk<span> to </span>health<span>. By reducing </span>air pollution<span> levels, countries can reduce the burden of disease from stroke, heart disease, lung cancer, and both chronic and acute respiratory diseases, including asthma.</span>
3 0
4 years ago
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In the fabrication of an electrical extension cord, the manufacturer wants to reduce the overall resistance of the wires in the
Bezzdna [24]

Answer:

Option B is correct.

Explanation:

The resistance of a material or wire is represented by the formula below.

R=(ρL)/A

where

  • R is resistance of wire
  • ρ is the resistivity of the material
  • A is the cross sectional area of wire
  • L is length of wire

Resistance increases with increase in length and resistivity which means options C and D are wrong.

A=(πd^{2})/4

An increase in diameter will result in a proportional increase in area

From the resistance formula, an increase in area will cause a reduction in the resistance of the material.Thus increased diameter of wire will lower the resistance of wire. Option B is correct

Have a great day

5 0
3 years ago
A body-centered cubic lattice has a lattice constant of 4.83 Ă. A plane cutting the lattice has intercepts of 9.66 Å, 19.32 Å, a
anastassius [24]

Answer:

Miller Indices are [2, 4, 3]

Solution:

As per the question:

Lattice Constant, C = 4.83 \AA

Intercepts along the three axes:

\bar{x} = 9.66 \AA

\bar{x} = 19.32 \AA

\bar{x} = 14.49 \AA

Now,

Miller Indices gives the vector representation of the atomic plane orientation in the lattice and are found by taking the reciprocal of the intercepts.

Now, for the Miller Indices along the three axes:

a = \frac{1}{9.66}

b = \frac{1}{19.32}

c = \frac{1}{14.49}

To find the Miller indices, we divide a, b and c by reciprocal of lattice constant 'C' respectively:

a' = \frac{\frac{1}{9.66}}{\frac{1}{4.83}} = \frac{1}{2}

b' = \frac{\frac{1}{19.32}}{\frac{1}{4.83}} = \frac{1}{4}

c' = \frac{\frac{1}{14.49}}{\frac{1}{4.83}} = \frac{1}{3}

7 0
3 years ago
Which sentences describe disavantages of burning fossil fuels instead of using hydrogen fuel cells
Aleksandr-060686 [28]

Answer:

Coal and oil release sulfur dioxide gas when they burn, which causes breathing problems for living creatures and contributes to acid rain. Fossil fuels release carbon dioxide when they burn, which adds to the greenhouse effect and increases global warming .

Explanation:

6 0
3 years ago
a. What is the peak wavelength for AM0? What temperature T corresponds to this peak wavelength for a blackbody source? Assuming
atroni [7]

Answer:

A) T = 5510 K , B)   I = 5,226 10⁷ W / m² , C)   I₂ = 1128 W / m²

Explanation:

A) The mass of air is defined as the ratio between the shortest path that sunlight must pass to reach the planet's surface and the length of the beam, is called AM

      Am = 1 / cos θ

The AM0 value corresponds to solar radiation in the outer part of the Earth's atmosphere.

The peak of this emission is the peak that emitted from the sun

       λ = 526 nm

To find the temperature that corresponds to this emission we use the Wien displacement law

       λ T = 2,898 10⁻³

      T = 2,898 10⁻³ / 526 10⁻⁹

      T = 5510 K

i) The radiance on the surface of the sun is

           I = P / A

We can calculate the potency by Stefan's law, for a black body

         P = σ A e T⁴

         P / A = σ e T⁴

The σ constant is value 5,670 10⁻⁸ W / m²K⁴, we will assume that the Sun emits as a black body, so e = 1

            I = sig T⁴

            I = 5,670 10⁻⁸  5510⁴

            I = 5,226 10⁷ W / m²

ii) the irradiation at a distance of 1 ua (1,496 1011 m)

Let's use the relationship

           P = I A

           I₁ A₁ = I₂ A₂

           I₂ = I₁ A₁ / A₂

 

The area of ​​a sphere is

          A = 4π R²

Let's replace

         I₂ = I₁ (r₁ / r₂)²

  Index 1 corresponds to the sun and the index to Earth that is an astronomical unit

        r₁ = 6.96 10⁸m        (Sun radius)

        r₂ = 1,498 1011 m    (Earth-Sun distance)

Calculous

       I₂ = 5,226 10⁷ (6.96 10⁸ / 1,498 10¹¹)²

       I₂ = 1.1281 10³ W / m²

       I₂ = 1128 W / m²

8 0
3 years ago
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