Answer:
The speed of the white puck immediately after the collision is 2.6 m/s.
Explanation:
Given that,
Two pucks are equal masses.
Speed of black puck = 1.5 m/s
According to given figure,
We need to calculate the speed of the white puck immediately after the collision
Using law of conservation of momentum
Put the value into the formula according to figure
Hence, The speed of the white puck immediately after the collision is 2.6 m/s.
Explanation:
The original acceleration is:
∑F = ma
10 N = (5 kg) a
a = 2 m/s²
If the mass is tripled, the new acceleration is:
∑F = ma
10 N = (15 kg) a
a = 0.67 m/s²
The acceleration is reduced by a factor of 3.
Answer:
The larger resistance value is 144 ohms and the smaller resistance value is 48 ohms.
Explanation:
Given that Resistance, R, is inversely proportional to Power, the largest value of power will yield the smallest value of resistance and vice versa.
The largest value of resistance will be:
P = V²/R
R = V²/P
R = 120²/100
R = 144 ohms
The smallest value of resistance will be:
R = 120²/300
R = 48 ohms
T<span>he relationship between wavelength and frequency is inverse.
This is as the wavelength increases the frequency decreases and as the wavelength decreases the frequency increases.
The light meets this equation that reflects the relationship between wavelength and frequency:
c = wavelength * frequency => wavelength = c / frequency
where c is the constant speed of light.
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Answer:
(C) The frequency decrease and intensity decrease
Explanation:
The Doppler effect describes the change in frequency or wavelength of a wave in relation to an observer who is moving relative to the wave source, or the wave source is moving relative to the observer, or both.
if the observer and the source move away from each other as is the case for this problem, the wavelength heard by the observer is bigger.
The frequency is the inverse from the wavelength, so the frequency heard will increase.
The sound intensity depends inversely on the area in which the sound propagates. When the buzzer is close, the area is from a small sphere, but as the buzzer moves further away, the wave area will be from a larger sphere and therefore the intensity will decrease.
