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Anastaziya [24]
4 years ago
13

A circular loop of flexible iron wire has an initial circumference of 165.0cm, but its circumference is decreasing at a constant

rate of 12.0cm/s due to a tangential pull on the wire. The loop is in a constant, uniform magnetic field oriented perpendicular to the plane of the loop of magnitude 0.500T. Find the emf induced in the loop, at the instant when 9.0s have passed. And find the direction

Physics
1 answer:
vovangra [49]4 years ago
6 0

Answer:

emf induced in the loop, at the instant when 9.0s have passed = 1.576 * 10 ⁻² V.

Direction is counter clockwise.

Explanation:

See attached pictures.

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1. A 1 kg cart moving with a speed of 3 m/s collides with a 2 kg cart at rest. If the carts stick together after the collision,
erica [24]

Answer:

The final speed of the two carts stuck together after the collision is 1 m/s

Explanation:

This is an example of an inelastic collision where two separate carts each with different momentum collide and become a single object.

The conservation of momentum (p) equation is: p_{1i}+p_{2i}=p_f where p_{1i} is the initial momentum of cart 1: p_{1i}=m_1\,*\,v_{1i}=1\,kg\,*\,3\,\frac{m}{s} = 3 \frac{kg*m}{s}

Notice that cart 2 is at rest, therefore its velocity is zero, which makes its initial momentum zero: p_{2i}=m_2\,*\,v_{2i}= 2\,kg \,*0\,\frac{m}{s} =0

The final momentum (p_f) for which we don't know the velocity (v_f) is the product of the final mass (addition of the two masses) times the final velocity of this new object (two carts stuck together):

p_f=(m_1+m_2)* v_f = 3\,kg\,*\,v_f

Now we re-write the conservation of momentum equation to isolate and obtain the unknown final velocity:

p_{1i}+p_{2i}=p_f\\3\,\frac{m*kg}{s}+0=3\,kg\,*\,v_f\\3\,\frac{m*kg}{s}=3\,kg\,*\,v_f\\v_f=\frac{3}{3}\, \frac{m}{s} \\v_f=1\,\frac{m}{s}

7 0
3 years ago
Two teams of nine members each engage in a tug of war. Each of the first team's members has an average mass of 64 kg and exerts
Serggg [28]

Answer:

a=0.13m/s^2

Explanation:

From the question we are told that

Mass of first team man m_1=64kg

Force of man first team man F_1=1350

Mass of second team man m_2=69kg

Force of man second team man F_2=1367N

Generally the equation for net force F_n is mathematically given by

F_n=9(m_1+m_2)a

9(m_1+m_2)a=9(f_2-f_1)

9(64+69)a=9(1367-1350)

a=\frac{9(1367-1350)}{9(64+69)}

a=0.127819m/s^2

Therefore the acceleration is given by

a=0.13m/s^2

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Answer:

True

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The radio transmitter generates the radio frequency

As you move away from the radio transmitter, the radio frequency decreases

The relationship between frequency and wavelength is inverse

As the frequency decreases the wavelength of the radio signal increases

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