What occurs during the process of condensation in the water cycle
2 answers:
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- 0.05 L needs to be added to the original 0.12 L solution in order to dilute it from 0.13 M to 0.23 M.
The dilution problem uses the equation :
The initial molarity (concentration) 0.13 M
The initial volume = 0.12 L
The desired molarity (concentration) = 0.23 M
The volume of the desired solution = ( 0.12 + x L )
Substituting values in above equation;
(0.13 M ) (0.12 L) = (0.23 M ) (0.12 L + x L)
0.0156 M L = 0.0276 M L + 0.23 x M L
- 0.012 M L = 0.23 x M L
x = - 0.05
Therefore, - 0.05 L needs to be added to the original 0.12 L solution in order to dilute it from 0.13 M to 0.23 M.
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Answer: The empirical formula of X is .
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of C = 62.4 g
Mass of H = 4.19 g
Mass of O = 33.2 g
Step 1 : convert given masses into moles.
Moles of C=
Moles of H=
Moles of O =
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =
For H =
For O =
The ratio of C: H: O = 2.5 : 2 : 1
Converting it into simple whole number ratios by multiplying by 2:
Hence the empirical formula of X is .