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Nastasia [14]
3 years ago
8

Water has a density of 0.997 g/cm^3 at 25 degrees C; ice has a density of 0.917 g/cm^3 at -10 degrees C. (question part a) If a

soft drink bottle whose volume is 1.50L is completely filled with water and then frozen to -10 degrees C, what volume does the ice occupy? (question part b) Can the ice be contained within the bottle?
Chemistry
2 answers:
KatRina [158]3 years ago
8 0
<span>1.5L x 0.05
= 0.075
= 1.425L

</span>Once melted ice will then take the same volume as before (10cm^3<span>), but it was dispersing only </span>9.5cm^3<span>, so the water level will rise to account for the additional .</span>5cm^3<span>. This is a fairly small amount (only about 5% of the volume of the melted water), but it's notable.
</span><span>
Therefore yes it can be contained.




</span>
Luden [163]3 years ago
4 0
Mass of water added:
0.997 x 1500
= 1495.5 grams

a) Volume = mass / density
Volume = 1495.5 / 0.917
Volume = 1630 cm³ = 1.63 L

b) The ice cannot be contained in the bottle as its volume exceeds that of the bottle.
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I need help solving this!
zmey [24]

Answer: Moles of hydrogen required are 4.57 moles to make 146.6 grams of methane, CH_{4}.

Explanation:

Given: Mass of methane = 146.6 g

As moles is the mass of a substance divided by its molar mass. So, moles of methane (molar mass = 16.04 g/mol) are calculated as follows.

Moles = \frac{mass}{molar mass}\\= \frac{146.6 g}{16.04 g/mol}\\= 9.14 mol

The given reaction equation is as follows.

C + 2H_{2} \rightarrow CH_{4}

This shows that 2 moles of hydrogen gives 1 mole of methane. Hence, moles of hydrogen required to form 9.14 moles of methane is as follows.

Moles of H_{2} = \frac{9.14}{2}\\= 4.57 mol

Thus, we can conclude that moles of hydrogen required are 4.57 moles to make 146.6 grams of methane, CH_{4}.

5 0
3 years ago
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Paha777 [63]

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Answer:

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