All categories

4 years ago

4. A truck has four times the mass of a car and is moving with twice the speed of the car.

Physics

1 answer:

slamgirl [31]4 years ago

3 0

Answer:

Relation between kinetic energy of truck and kinetic energy of car is given as

$K_t = 16 K_c$

Explanation:

As we know that mass of truck is four times the mass of car

$m_t = 4 m_c$

and the speed of truck is double that of speed of car

$v_t = 2v_c$

now we have kinetic energy of the truck is given as

$K_t = \frac{1}{2}m_t v_t^2$

similarly kinetic energy of car is given as

$K_c = \frac{1}{2}m_cv_c^2$

now from above two equations we have

$\frac{K_t}{K_c} = \frac{\frac{1}{2}m_tv_t^2}{\frac{1}{2}m_cv_c^2}$

$\frac{K_t}{K_c} = 4(4) = 16$

so we have

$K_t = 16 K_c$

You might be interested in

1. In a single atom, no more than 2 electrons can occupy a single orbital? A. True B. False

Studentka2010 [4]

1. In a single atom, no more than 2 electrons can occupy a single orbital? A. True

2. The maximum number of electrons allowed in a p sublevel of the 3rd principal level is?
B.6

3. A neutral atom has a ground state electronic configuration of 1s^2 2s^2. Which of the following statements concerning this atom is/are correct?
B. All of the above.

4 0

4 years ago

Read 2 more answers

A branch falls from a tree how fast is the branch moving after drug .28 seconds

alexdok [17]

Acceleration=9.81m/s^2
initial velocity=0m/s
time=.28s

We have to find final velocity.

The equation we use is

Final velocity=initial velocity+acceleration x time

Vf=0m/s+(9.81m/s^2)(.28s)
Vf=2.7468m/s

We would round this to:

Vf (final velocity)=2.7m/s

6 0

3 years ago

Find the kinetic energy of an electron whose de broglie wavelength is 34.0 nm.

dezoksy [38]

The De Broglie wavelength of the electron is
$\lambda=34.0 nm=34 \cdot 10^{-9} m$
And we can use De Broglie's relationship to find its momentum:
$p= \frac{h}{\lambda}= \frac{6.6 \cdot 10^{-34} Js}{34 \cdot 10^{-9} m}=1.94 \cdot 10^{-26} kg m/s$

Given $p=mv$ , with m being the electron mass and v its velocity, we can find the electron's velocity:
$v= \frac{p}{m}= \frac{1.94 \cdot 10^{-26} kgm/s}{9.1 \cdot 10^{-31} kg}= 2.13 \cdot 10^4 m/s$

This velocity is quite small compared to the speed of light, so the electron is non-relativistic and we can find its kinetic energy by using the non-relativistic formula:
$K= \frac{1}{2}mv^2= \frac{1}{2}(9.1 \cdot 10^{-31} kg)(2.13 \cdot 10^4 m/s)^2=2.06 \cdot 10^{-22} J$

3 0

3 years ago

At the surface of Jupiter's moon Io, the acceleration due to gravity is 1.81 m/s2 . A watermelon has a weight of 54.0 N at the s

butalik [34]

Answer:

$m=5.51Kg$