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2 years ago

Decomposition reaction of Ag3N

Chemistry

1 answer:

DanielleElmas [232]2 years ago

3 0

Answer: 2 Ag3N => 6 Ag + N2

Explanation: Decomposition is expressed through this generic equation:

AX => A+ X

After the reaction balance the chemical reaction.

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How many atoms are in 73.9g of potassium oxide

denis-greek [22]

Answer: $4.69(10)^{23} atoms$

Explanation:

Firstly, we have to find the Molecular mass of potassium oxide ( $K_{2}0$ ):

$K$ atomic mass: 39 u

$O$ atomic mass: 16 u

$K_{2}O$ molecular mass: $39(2) g/mol+16g/mol=94 g/mol$

This means that in 1 mole of $K_{2}O$ there are $94 g$ and we need to find how many moles there are in $73.9 g$ $K_{2}O$ :

1 mole of $K_{2}O$ ----- $94 g$ of $K_{2}O$

$X$ ----- $73.9 g$ of $K_{2}O$

$X=\frac{(73.9 g)(1 mole)}{94 g}$

$X=0.78 mole$ This is the quantity of moles in 73.9 g of potassium oxide

Now we can calculate the number of atoms in 73.9 g of potassium oxide by the following relation:

$N_{atoms}=(X)(N_{A})$

Where:

$N_{atoms}$ is the number of atoms in 73.9g of potassium oxide

$N_{A}=6.0221(10)^{23}/mol$ is the Avogadro's number, which is determined by the number of particles (or atoms) in a mole.

Then:

$N_{atoms}=(0.78 mole)(6.0221(10)^{23}/mol)$

$N_{atoms}=4.69(10)^{23} atoms$ This is the quantity of atoms in 73.9g of potassium oxide

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3 years ago