Question

I am stuck... Chemistry is the worst and anything is appreciated!

Answer 1

I think it is 110 mL but I’m not totally sure.

Answer 2

Answer:

2.78 mL of solution will be needed to make 4.5 M solution with 0.50 grams of NaOH.

Explanation:

Moles of sodium hydroxide = n

$n=\frac{0.50 g}{40 g/mol}=0.0125 mol$

$Moles (n)=Molarity(M)\times Volume (L)$

Volume of sodium hydroxide solution =V

Molarity of the sodium nitrate solution = 4.5 M

$V=\frac{0.0125 mol}{4.5 M}=0.00278 L$

V  = 0.00278 L = 2.78 mL

2.78 mL of solution will be needed to make 4.5 M solution with 0.50 grams of NaOH.