Question

More people end up in U.S. emergency rooms because of fall-related injuries than from any other cause. At what speed v would someone hit the ground who accidentally steps off the top rung of a 7.00 ft tall stepladder

Answer 1

Answer:

$v_{f}=6.47m/s$

Explanation:

Given data

Distance d=7.00 ft= 7*(1/3.281) =2.1336m

Initial velocity vi=0m/s

To find

Final velocity

Solution

From Kinematic equation we know that:

$v_{f}^{2} =v_{i}^{2}+2gd\\v_{f}^{2}=0+2(9.81m/s^{2} ) (2.1336m)\\v_{f}^{2}=41.86\\v_{f}=\sqrt{41.86}\\v_{f}=6.47m/s$