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Zielflug [23.3K]
3 years ago
14

the coefficient of static friction between a 40 kg picnic table and the ground below is .43. what is the greatest horizontal for

ce that could be exerted on the table while it remains stationary?
Physics
2 answers:
Mashcka [7]3 years ago
6 0

Answer:

The greatest horizontal force that can be exerted without moving the table is 168.56N.

Explanation:

The maximum friction force is determined from the coefficient of static friction as follows:

F_{fr}=\mu\cdot F_{norm} = 0.43\cdot F_{norm}

where the the normal force is exerted by the ground as a reaction to the weight of the table, and has same magnitude as but opposite direction to the gravitational force on the table:

F_{fr} = 0.43\cdot 40kg\cdot 9.8 \frac{m}{s^2} = 168.56 N

This is the <em>maximum</em> static force, so the friction force will be matching and opposing any horizontal force up to 168.56N.

Gre4nikov [31]3 years ago
4 0
The force equals the coefficient of static friction times the weight. Use gravity g=9.8 m/s^2
0.43*40*9.8=16.856 N
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Please mark my answer as brainliest?

3 0
3 years ago
Over a 24-hour period, the tide in a harbor can be modeled by one period of a sinusoidal function. the tide measures 5.15 ft at
RSB [31]
<span>f(x) = 5.05*sin(x*pi/12) + 5.15

   First, you need to determine the period of the function. The period will be the time interval between identical points on the sinusoidal function. For this problem, the tide is rising and at 5.15 at midnight for two consecutive days. So the period is 24 hours. Over that 24 hour period, we want the parameter passed to sine to range from 0 to 2*pi. So the scale factor for x will be 2*pi/24 = pi/12 which is approximately 0.261799388. The next thing to note is the magnitude of the wave. That will simply be the difference between the maximum and minimum values. So 10.2 ft - 0.1 ft = 10.1 ft. And since the value of sine ranges from -1 to 1, we need to divide that magnitude by 2, so 10.1 ft / 2 = 5.05 ft.

   So our function at this point looks like f(x) = 5.05*sin(x*pi/12) But the above function ranges in value from -5.05 to 5.05. So we need to add a bias to it in order to make the low value equal to 0.1. So 0.1 = X - 5.05, 0.1 + 5.05 = X, 5.15 = X. So our function now looks like:
  f(x) = 5.05*sin(x*pi/12) + 5.15

   The final thing that might have been needed would have been a phase correction. With this problem, we don't need a phase correction since at X = 0 (midnight), the value of X*pi/12 = 0, and the sine of 0 is 0, so the value of the equation is 5.15 which matches the given value of 5.15. But if the problem had been slightly different and the height of the tide at midnight has been something like 7 feet, then we would have had to calculate a phase shift value for the function and add that constant to the parameter being passed into sine, making the function look like:
 f(x) = 5.05*sin(x*pi/12 + C) + 5.15
  where
 C = Phase correction offset.

   But we don't need it for this problem, so the answer is:
 f(x) = 5.05*sin(x*pi/12) + 5.15

   Note: The above solution assumes that angles are being measured in radians. If you're using degrees, then instead of multiplying x by 2*pi/24 = pi/12, you need to multiply by 360/24 = 15 instead, giving f(x) = 5.05*sin(x*15) + 5.15</span>
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3 years ago
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solniwko [45]

Answer:

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