The correct answer is :
According to classical electrodynamics, light energy is a wave that is absorbed by atoms in a manner similar to how an object absorbs radiant heat. So, the atoms of a metal would absorb more energy the brighter the light was. It would be feasible for an electron in a metal to break free from its atoms if it received enough energy from the incoming wave. The more energy absorbed, the more energetic the metal's released electrons would be. Additionally, no electrons could conceivably be ejected until each atom had enough light energy. Light intensity was far more important than light frequency.
In many respects, the photo-electric effect contradicted this strategy:
- If the light was below a specific frequency, no matter how bright it was, no electrons were released. Increased light intensity increased the number of electrons that were released, but not their energy, if the light was above this frequency.
- Regardless of how weak the light was, electrons were nearly immediately emitted from the metal.
- Even though the intensity of the light was reduced, an increase in its frequency led to more energising electrons leaving the metal.
To learn more about photo-electric effect refer the link:
brainly.com/question/25630303
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High-frequency sound waves have a shorter wavelength and higher pitch. Frequency, loosely defined, is a measure of how long it takes for a single wavelength to pass a point, so the higher the frequency, the faster the wave is moving, and thus the shorter the wavelength. Pitch (a term used in music) is just another word for frequency, so a wave with high frequency automatically has high pitch.
Answer:
Please help on any part you can. I know it is a lot but any help I’d greatly appreciate. I attempted the problem but still do not understand. Thank you so much!
Explanation:
Please help on any part you can. I know it is a lot but any help I’d greatly appreciate. I attempted the problem but still do not understand. Thank you so much!