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3 years ago

Which equation represents a function?

Mathematics

1 answer:

Maurinko [17]3 years ago

6 0

All the answers except C has a Vertical Line when graphed. It must pass the Vertical line test in order to be a function.

Vertical Line Test: If you can draw a vertical line anywhere on a graph so that it hits the graph in more than one spot, then the graph is NOT a function.

C.) can pass the test since it's a horizontal line.

Hope this helps!

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Rick won 27 tickets playing a game. To get a prize, he needs to win at least 30 more tickets. How many more tickets can he won’t

ElenaW [278]

Answer: 56

Step-by-step explanation:

30 is a win so what is 1 least than 30 is 29.

So 27 add 29 is equal to 56

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4 years ago

I need an equation for the line parallel to the given line that contains C. <br><br> Thanks so much!

gulaghasi [49]

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3 years ago

Read 2 more answers

X starts at 15 and subtract 3. Y starts at 14 and subtract 3

Andre45 [30]

Answer:

x: 12 9 6 3

y: 11 8 5 2

Step-by-step explanation:

Every box is the previous number minus 3. For x, they say to start with 15 and subtract 3, so the first box is 15-3. The second box is the previous box, 12, minus 3 and so on. Y is done the same way. Hope this is helpful :)

4 0

3 years ago

After completing the square, what are the solutions to the quadratic equation

Fiesta28 [93]

Answer:

$x_1= \frac{\sqrt{{29}}}{2} +\frac{7}{2}\\\\x_2= -\frac{\sqrt{{29}}}{2} +\frac{7}{2}$

Step-by-step explanation:

1. Subtract 9 from both sides of the equation:

$x^2 - 7x+9-9 = 4-9\\\\x^2 - 7x= -5$

2. Notice that the coefficient of "x" is 7. Then:

$(\frac{7}{2})^2=\frac{49}{4}$

3. Add $\frac{49}{4}$ to both sides of the equation:

$x^2 - 7x+\frac{49}{4}= \frac{49}{4}-5\\\\x^2 - 7x+\frac{49}{4}= \frac{29}{4}$

4. Completing the square, you get:

$(x -\frac{7}{2})^2= \frac{29}{4}$

5. To find the solutions, you must square-root both sides of the equation, simplify, and solve for "x". Then, you get:

$\sqrt{(x -\frac{7}{2})^2}= \±\sqrt{\frac{29}{4}}\\\\x -\frac{7}{2}=\±\frac{\sqrt{{29}}}{2} \\\\x= \±\frac{\sqrt{{29}}}{2} +\frac{7}{2}\\\\\\x_1= \frac{\sqrt{{29}}}{2} +\frac{7}{2}\\\\x_2= -\frac{\sqrt{{29}}}{2} +\frac{7}{2}$