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4 years ago

9

Sunlight, when viewed through a prism or a diffraction grating, shows all of the colors of visible light. This is an example of

a
(A) bright line spectrum
(B) continuous spectrum
(C) infrared spectrum
(D) visible spectrum
(E) ultraviolet spectrum

1 answer:

nata0808 [166]4 years ago

8 0

A spectrum that includes all colors and doesn't have
any gaps in it is a continuous spectrum.

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Explain what a mole of copper (Cu) atoms and a mole of Sulfur Dioxide (SO2) molecules have in common.

evablogger [386]

Answer:

The amount of molecules → 6.02×10²³

Explanation:

Avogadro Number (NA) is the amount of particles that are contained in 1 mol of anything.

It does not matter the mass of compounds, or molecules, 1 mol has 6.02×10²³ particles, the same number for every compound.

1 mol of H₂O that weighs 18 grams has 6.02×10²³ molecules

1 mol of sucrose, that weighs 342 g has 6.02×10²³ molecules

Generally, the NA is the number of atoms in 12 grams of the carbon-12 isotope.

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3 years ago

Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simulta

Brut [27]

Answer:

The molar mass of unknown gas is 145.82 g/mol.

Explanation:

Volume of oxygen gas effused under time t = 8.24 mL

Effusion rate of oxygen gas = $R=\frac{8.24 mL}{t}$

Molar mass of oxygen gas = 32 g/mol

Volume of unknown gas effused under time t = 3.86 mL

Effusion rate of unknown gas = $R'=\frac{3.86 mL}{t}$

Molar mass of unknown gas = M

Graham's Law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

$\frac{R}{R'}=\sqrt{\frac{M}{32 g/mol}}$

$\frac{\frac{8.24 mL}{t}}{\frac{3.86 mL}{t}}=\sqrt{\frac{M}{32 g/mol}}$

$M=\frac{32 g/mol\times 8.24 \times 8.24}{3.86\times 3.86}=145.82 g/mol$

4 0

3 years ago

If the temperature of an object is 335 K, how would this be expressed on the Celsius scale?

Arturiano [62]

C it the correct answer

5 0

3 years ago

Which of the following alkyl halides is most likely to undergo rearrangement in an SN1 reaction? Please explain your answer.

Mashcka [7]

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7 0

3 years ago

Calculate the change in enthalpy for the reaction. (Use 1.0 g/mL as the density of the solution and 4.18 J/(g⋅∘C) as the specifi

Dovator [93]

Here is the full question

Instant cold packs, often used to ice athletic injuries on the field, contain ammonium nitrate and water separated by a thin plastic divider. When the divider is broken, the ammonium nitrate dissolves according to the following endothermic reaction: NH4NO3(s)→NH+4(aq)+NO−3(aq) In order to measure the enthalpy change for this reaction, 1.25 g of NH4NO3 is dissolved in enough water to make 25.0 mL of solution. The initial temperature is 25.8 ∘C and the final temperature (after the solid dissolves) is 21.9 ∘C. Part A Calculate the change in enthalpy for the reaction in kilojoules per mole. (Use 1.0g/mL as the density of the solution and 4.18J/g⋅∘C as the specific heat capacity.) Express your answer to two significant figures and include the appropriate units. ΔHrxn = ??? kJ/mol

Answer:

26 kJ / mol

Explanation:

Given that;

The mass of NH₄NO₃ = 1.25 g

Number of moles of NH₄NO₃ = Mass of NH₄NO₃ / Molar Mass of NH₄NO₃

Number of moles of NH₄NO₃= 1.25 g / 80.043 g/mol

Number of moles of NH₄NO₃= 0.016 mol

Volume of solution = 25.0 mL

Density of Solution = 1.0g/mL

Since; $density = \frac {mass} {volume}$

Mass of Solution = Density x Volume

= 1.0g/mL × 25.0mL

= 25 g

Heat Generated (Q) = $mc \delta T$

Q= 25g × 4.18 J/g°C x (25.8°C - 21.9°C)

Q = 407.55 J

Q = 407 × 10 ⁻³ kJ

Q = 0.40755 kJ

Δ $H_{rxn}$ = $\frac{Heat generated(Q)}{number of molesof NH_4NO_3}$

= $\frac {0.40755 kJ}{ 0.016 mol}$

= 25.47 kJ/ mol

~ 26 kJ / mol

Therefore, the change in enthalpy for the reaction in kilojoules per mole = 26 kJ / mol

8 0

3 years ago