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ludmilkaskok [199]
3 years ago
9

In the formula XSO4 the symbol X could represent the element

Chemistry
2 answers:
Soloha48 [4]3 years ago
7 0

Answer: X could represent the element of oxidation state (+2) such as (Mg2+, Pb2+, Ba2+, Ca2+, Ba2+, Zn2+, ....etc)

Explanation:

  • The formula of the compound XSO4 is a neutral compound that the algebraic summation of the oxidation states of different elements in it must be zero.
  • The group SO4 has the oxidation state (2-), that S has (6+) oxidation state and O has (2-) oxidation state, so the oxidation of SO4 = (6+) + (-2*4) = -2.
  • It is clear that X must have the oxidation state 2+.
  • So, X could be represents by many different elements such as (Mg2+, Pb2+, Ba2+, Ca2+, Ba2+, Zn2+, Fe2+, ....etc)
Lapatulllka [165]3 years ago
7 0
X represents group 5A by my periodic table. P2O5 is an example. <span>Since there's charge specified, it must be a neutral atom. For this, each of the X would need a +5 charge. On the other hand, if it's in group 15, then it can form a covalent bond, since each atom in group 15 can share 5 atoms.</span>
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mass = 9.925 g 
density = 0.9975 g/ml
density = \frac{mass}{volume} 
so actual volume = \frac{mass}{density} = \frac{9.925}{0.9975} = 9.95 mL
Percentage Error = \frac{measured volume - Actual volume}{actual volume} x 100 
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Cuantos moles de CO2 se requieren para reaccionar con 2 moles de Ba (OH)2
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Answer:

hola soy jess, tu respuesta esta aqui

¿cuantos moles de CO2 se requiere para reaccionar 2 moles de Ba(OH)2

2 mol Ba(OH)₂ × \frac{1molCO_{2} }{1molBa (OH)_{2}}

1molBa(OH)

2

1molCO

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How many moles of bromine atoms are in 2.60×10^2 grams of bromine?
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A 1.800-g sample of solid phenol (C6H5OH(s)) was burned in a bomb calorimeter whose total heat capacity is 11.66 kJ/?C. The temp
vichka [17]

Answer:

The balanced chemical equation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

Heat of combustion per gram of phenol is 32.454 kJ/g

Heat of combustion per gram of phenol is 3,050 kJ/mol

Explanation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

Heat capacity of calorimeter = C = 11.66 kJ/°C

Initial temperature of the calorimeter = T_1= 21.36^oC

Final temperature of the calorimeter = T_2= 26.37^oC

Heat absorbed by calorimeter = Q

Q=C\times \Delta T

Heat released during reaction = Q'

Q' = -Q ( law of conservation of energy)

Energy released on combustion of 1.800 grams of phenol = Q' = -(58.4166 kJ)

Heat of combustion per gram of phenol:

\frac{Q'}{1.800 g}=\frac{-58.4166 kJ}{1.800 g}=32.454 kJ/g

Molar mass of phenol = 94 g/mol

Heat of combustion per gram of phenol:

\frac{Q'}{\frac{1.800 g}{94 g/mol}}=\frac{-58.4166 kJ\times 94 g/mol}{1.800 g}=3,050 kJ/mol

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2 years ago
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