We are given with
Cobalt phosphate - CoPO4
We are asked for the net ionic equation for the phosphate dissolving in H3O+
The net ionic equation is
CoPO4 (s) + H3O+ (aq) -----> HPO42- (aq) + Co3+ (aq) + H2O *(l)
Answer:
900 J/mol
Explanation:
Data provided:
Enthalpy of the pure liquid at 75° C = 100 J/mol
Enthalpy of the pure vapor at 75° C = 1000 J/mol
Now,
the heat of vaporization is the the change in enthalpy from the liquid state to the vapor stage.
Thus, mathematically,
The heat of vaporization at 75° C
= Enthalpy of the pure vapor at 75° C - Enthalpy of the pure liquid at 75° C
on substituting the values, we get
The heat of vaporization at 75° C = 1000 J/mol - 100 J/mol
or
The heat of vaporization at 75° C = 900 J/mol
Answer:
law of conservation of mass
Explanation:
self explanatory
Molarity is measured in moles per Liter. If there are 1.35 g/mL, find out how many grams there are in a liter of solution.
If there are 1000 mL in one liter, we can multiply by 1000 to get g/L
1.35 g/mL x 1 Liter/1000 mL = 1350 g per Liter of solution
By weight, the NaOH is 33% or .33
1350 g x .33 = 445.5 g of NaOH
Molar mass of NaOH is 39.997 g
445.5 g x 1 mol NaOH/39.997 g = 11.13833538 moles per Liter
Rounded to significant figures, the answer is 11 mol/L NaOH
