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Olin [163]
3 years ago
12

True or False:Excessive thermal energy will result in the removal of salt from the oceans.

Chemistry
1 answer:
Mrrafil [7]3 years ago
3 0

Answer:

false

Explanation:

the excessive heat would cause the water to evaporate so it wouldn't remove the salt it would remove the water. what you would get would be an ocean bed with tons of salt at the bottom.

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While you are doing your homework, a friend looks over your shoulder and sees electron configurations on your paper. "Whats That
zzz [600]

Answer:

The energy of atomic orbitals increases as the principal quantum number, n, increases. In any atom with two or more electrons, the repulsion between the electrons makes energies of subshells with different values of l differ so that the energy of the orbitals increases within a shell in the order s < p < d < f.

Explanation:

7 0
3 years ago
What is the formula mass/molar mass of H2CO2
____ [38]

H - 1.01

C - 12.01

0 - 16.00

2(1.01) + 12.01 + 2(16.00) = 46.03 g/mol

4 0
3 years ago
Select the sentences in the paragraph that explain only the dark lines that are produced in the absorption spectra. Select all t
Nady [450]

Answer:

Gaps are produced in the light spectra that correspond to wavelengths of absorbed photons.

Explanation:

When electrons in atoms absorb energy, they move from a lower energy level to a higher energy level. With time, they revert to the their original energy state emitting a photon of light of appropriate wavelength.

The absorbed photons do not show up in the spectrum. They appear as dark lines in the spectrum. Hence, the absorption spectrum is the exact inverse of the emission spectrum. The  dark lines in the spectrum indicates that the colors that ought to occupied those points there have been absorbed.

5 0
3 years ago
Describing Diffusion
yaroslaw [1]

Answer:

its the 3rd option.

the molecules move from region of higher concentration to a region of lower concentration.

Explanation:

please do give me brainliest if this helped you.

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3 0
3 years ago
1. When 50.0 mL of water at 80.0°C was mixed with 50.0 mL of water in a calorimeter at
ddd [48]

Answer:

The heat capacity of the calorimeter is 5.11 J/g°C

Explanation:

Step 1: Given data

50.0 mL of water with temperature of 80.0 °C

Specific heat capacity of water = 4.184 J/g°C

Consider the density of water = 1g/mL

50.0 mL of water in a calorimeter at 20.0 °C

Final temperature = 47.0 °C

Step 2: Calculate specific heat capacity of the water in calorimeter

Q = Q(cal) + Q(water)

Q(cal) = mass * C(cal) * ΔT

Qwater = mass * Cwater * ΔT

Qcal = -Qwater

mass(cal) * C(cal) * ΔT(cal) =  mass(water) * C(water) * ΔT(water)

50 grams * C(cal) * (47.0 - 20.0) =- 50grams * 4.184 J/g°C * (47-80)

1350 * C(cal) = 6903.6

C(cal) = 5.11 J/g°C

The heat capacity of the calorimeter is 5.11 J/g°C

8 0
3 years ago
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