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Olin [163]
3 years ago
12

True or False:Excessive thermal energy will result in the removal of salt from the oceans.

Chemistry
1 answer:
Mrrafil [7]3 years ago
3 0

Answer:

false

Explanation:

the excessive heat would cause the water to evaporate so it wouldn't remove the salt it would remove the water. what you would get would be an ocean bed with tons of salt at the bottom.

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Please help!!!Which statement accurately describes relationship between weight and mass? If the picture is black just don’t answ
Mars2501 [29]

Answer:

A

Explanation:

Mass is a raw measurement, weight is effected by gravity

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3 years ago
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1.hydrogen
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A car with a mass of 1,100 kg is moving with a velocity of 30 m/s due east . What is the moment?
dexar [7]
Momentum = (mass) x (velocity) = (1,100) x (30) =

33,000

kg-m/sec due east

6 0
3 years ago
Combustion of hydrocarbons such as undecane (C_11H_24) produces carbon dioxide, a "greenhouse gas." Greenhouse gases in the Eart
bekas [8.4K]

Answer:

Volume of carbon dioxide is 428.23 L.

Explanation:

Below is the chemical reaction or chemical equation for the combustion of hydrocarbons such as undecane into carbon dioxide.

C_{11}H_{24}(l) + 17O_{2}(g) \to 11CO_{2} (g) + 12H_2O(g)

Here, undecane is in liquid form that reacts with gaseous oxygen (combustion)  and produces carbon dioxide and water as a product in the gaseous form.

The molar mass of undecane = 156.31 g/mol.

\text{Number of moles} = \frac{260g}{156.31g/mol} = 1.66 \ mol.

From the equation, it can be seen that 1 mole of undecane produces 11 moles of carbon dioxide. Therefore, 1.66 mol will produce 18.26 mol of carbon dioxide.

Now find the volume of 18.26 mol of carbon dioxide when the temperature is 13 degrees Celsius and pressure is 1 atm.

V = \frac{nRT}{P} \\

V = \frac{18.26 \times 0.082 \times 286 \ K}{1atm} \\

V = 428.23 \ L

6 0
3 years ago
The addition of 0.275 L of 1.62 M KCl to a solution containing Ag+ and Pb2+ ions is just enough to precipitate all of the ions
musickatia [10]

Answer:

The mass of PbCl₂ is 45.88 grams and the mass of AgCl is 16.48 grams.

Explanation:

As mentioned in the given question, the addition of 0.275 L of 1.62 M KCl is done in a solution that comprise Ag⁺ and Pb²⁺ ions so that all the ions get precipitated. Therefore, the moles of KCl present is,  

Moles of KCl = 0.275 L × 1.62 M = 0.445 moles

Now the reaction will be,  

Ag⁺ + Pb²⁺ + KCl ⇒ AgCl + PbCl₂ + 3K⁺

Now let us assume that the formation of x moles of AgCl and y moles of PbCl₂ is taking place.  

Therefore, mass of AgCl will be x × molecular mass, which will be equal to x × 143.32 grams = 143.32 x grams

Now the mass of PbCl2 formed will be,  

y × molecular mass = y × 278.1 grams = 278.1 y grams

Now the total precipitate will be,  

62.37 grams = 143.32 x + 278.1 y -----------(i)

Now as AgCl and PbCl₂ requires 1:2 ratio of KCl, this shows that x moles of AgCl will require x moles of KCl and y mol of PbCl₂ will require 2*y moles of PbCl₂. Therefore,  

x + 2y = total mass of KCl

x + 2y = 0.445 moles ------ (ii)

On solving equation (i) and (ii) we get,  

x as 0.115 and y as 0.165

Now the mass of AgCl will be,  

143.32 × 0.115 = 16.48 grams

The mass of PbCl₂ will be,  

278.1 × 0.165 = 45.88 grams.  

3 0
3 years ago
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