<h2>
Answer: C.Monogamy </h2>
Explanation:
Monogamy is a term that refers to the sentimental and sexual bond that <u>does not allow the multiplicity of spouses.
</u>
This means that love relationships are based on exclusivity, on maintaining a unique bond with your partner, refusing to develop the same kind of union or the same actions with other people.
Answer:
kinetic friction may be greater than 400 N or smaller than 400 N
Explanation:
As we know that maximum value of static friction on the rough surface is known as limiting friction and the formula of this limiting friction is known as

now when object is sliding on the rough surface then the friction force on that surface is known as kinetic friction and the formula of kinetic friction is known as

now we know that

so here value of limiting static friction force is always more than kinetic friction
also we know that
initially when body is at rest then static friction value will lie from 0 N to maximum limiting friction
and hence kinetic friction may be greater than static friction or if the static friction is maximum limiting friction then kinetic friction is smaller than static friction
so kinetic friction may be greater than 400 N or smaller than 400 N
Its C. Decreasing its mass
Answer:
248 years
Explanation:
The last time this happened was from 1979 to 1999. It won't happen again until 2227.
Explanation:
This problem bothers elastic collision.
Given data
Mass m1= 25kg
Initial velocity u1= 5m/s
Final velocity v1= 1.5m/s
Mass m2= 35kg
Initial velocity u2=?
Final velocity v2 = 4.5m/s
A. To find the initial velocity of the 35kg car, let us Apply the principle of conservation of energy
m1u1+m2u2= m1v1+m2v2
25*5+ 35*u2= 25*1.5+ 35*4.5
125+35u2= 37.5+157.5
125+35u2=195
35u2= 195-125
35u2= 70
u2= 2m/s
The initial velocity is 2m/s
B. Totally not kinetic energy before impact
KE= 1/2m1u1²+ 1/2m2u2²
KE= (25*5²)/2+ (35*2²)/2
KE= 625/2 +140/2
KE= 312.5+70
KE= 382.5J
Total kinetic energy after impact
KE=1/2m1v1²+ 1/2m2v2²
KE= (25*1.5²)/2 +(35*4.5²)/2
KE= 56.25/2 +708.75/2
KE=28.125 +354.375
KE= 382.5J
We can see that energy is conserved
Kinetic energy before and after impact remains unchanged